A jet travels 1464 mi against the wind in 2 hours and 1704 mi with the wind in the same amount of time. What is the rate of the
jet in still air and what is the rate of still wind?
1 answer:
The jet rate against wind is 732 mi an hour (1464/2) and 852 with the wind (1704/2)
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Answer:
7
Step-by-step explanation:
-63/-9
7
1)
|-6-2|=|-8|=8
2)
G and I
3)
|-6+2|= |-4|=4
the point that is 4 units away from H and K is I
I=-2
Answer:
1.2
Step-by-step explanation:
Two negatives = one positive
So:
- (-14) = + 14
Add:
48 + 14 = 62
62 is your answer
hope this helps
If you want to isolate h, move all terms to the other side, leaving h behind.
A=1/2h(a+b)
2A=1h(a+b)
2A/a+b=h
Hope I helped :)
