Convection is when cool air sinks and warm air rises. i am not 100% sure though
Answer:
B - (C , Al, P, Cl)
Explanation:
How I got this answer was by looking at my periodic table it shows you how much it contains by the Atomic number.
Atomic number on C (Carbon) is- 6
Atomic number on Al (Aluminum) is - 13
Atomic number on P (Phosphorus) is - 15
Atomic number on Cl (Chlorine) is - 17
Now it says least to greatest and the other options are wrong I did the work for you hope this helps :)) I also had this project you didnt ask but the answer for the The Lesson are {B E M S} which as the code numbers are gonna be -7494- Im glad to help if you need more help I will give you the other answers as well :) !
From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.
Therefore; R1/R2 = √mm2/√mm1
The molecular mass of Carbon dioxide is 44 g
Hence; 1.8 = √(44/x
3.24 = 44/x
x = 44/3.24
= 13.58
Therefore, the molar mass of the other gas is 13.58 g/mol
Mass fraction has been the mass of an individual element with respect to the compound. The mass fraction of chloride in calcium chlorate is 0.171.
<h3>What is meant by a mass fraction?</h3>
Mass fraction has been defined as the ratio of the masses of the individual elements present in a compound to the total mass of the molecule or compound.
The formula for a mass fraction (w) is given as,
Mass fraction (w) = mass ÷ total mass
Given,
Mass of chlorine = 35.453 grams per mole
The molar mass of calcium chlorate (Ca(ClO₃)₂) = 206.98 grams per mole
Substituting and solving the values above as
w = mass of chlorine ÷ total mass of calcium chlorate
w = 35.453 ÷ 206.98
w = 0.171
Therefore, the mass fraction of Cl in calcium chlorate is 0.171.
Learn more about mass fraction, here:
brainly.com/question/14470971
#SPJ4
The POH of a 2.70 x10^-11 solution of lithium hydroxide(LiOH) is 10.6
calculation
POH= -log (OH-)
write the equation for dissociation of LiOH
LiOh---> Li^+(aq) + OH-(aq)
from the equation above the ratio LiOH: OH is 1:1 therefore the concentration of OH- =2.70 x10 ^-11
that is - log (2.70 x10^-11) = 10.6