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natima [27]
3 years ago
5

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional

questions.
Online Content: Site 1

How might physical weathering affect a sample? (site 1) (hurry im begging u!)
Chemistry
2 answers:
Vlad [161]3 years ago
7 0
Can anyone help me with my one question on my stuff?
Paha777 [63]3 years ago
7 0

Answer:

Sorry I was late but here you go

Explanation:

Physical weathering can affect a sample by changing the characteristics of the rock and they can be changed into boulders, cobbles, pebbles, sand, silt, clay, and colloids.

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Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

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How much heat in kJ is produced by the oxidation of 18.6 g of Mn?
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