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Tema [17]
3 years ago
12

Is a negatively ionized lithium paste a conductor or insulator

Physics
1 answer:
Elenna [48]3 years ago
5 0

Answer:

A negatively ionized lithium paste is a conductor.

Explanation:

A conductor is a material that conducts electricity. In other words, a conductor has little resistance to the movement of electric charge or electrons when an electric field is applied.

Insulating materials for electricity are those that offer a certain resistance to the movement of electrons or electric current. In other words, an electrical insulator is a material with a low capacity for conducting electricity.

The best conductors of electric current are metals due to the free electron clouds that favor the circulation of electric current through them.

So, <u><em>a negatively ionized lithium paste is a conductor. </em></u>

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Explain why you poured the ester into water before you identify the smell ?
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You will pour the ester into water before you identify the smell because the smell is mixed with the smell of a carboxylic acid. with the use of the water the carboxylic acid will dissolved in it, while the ester will form a layer because it is not soluble in water, and you will smell it clearly
3 0
3 years ago
Explain the difference between how intrusive and extrusive igneous rock form and how those formation processes affect the minera
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Extrusive molten rocks are formed from lava while the intrusive molten rocks are formed from magma.

<u>Explanation:</u>

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6 0
4 years ago
In a nuclear power plant, uranium atoms ______
motikmotik

Answer:

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4 0
3 years ago
A lever is used to lift a heavy rock. The rock has a mass of 800 N. It requires 200 N of force to lift the rock using the lever.
inna [77]

Answer:

The answer for this solution is 4

Explanation:

MA=L/E

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5 0
3 years ago
A "gauge 8" jumper cable has a diameter d of 0.326 centimeters. The cable carries a current I of 30.0 amperes. The electric fiel
AveGali [126]

Answer:

0.0979 N/c

Explanation:

Electric field, E is given as a product of resistivity and current density

E=jP where P is resistivity and j is current density

But the current density is given as

j=\frac {I}{A} where I is current and A is area and A=\pi r^{2}

Substituting this into the first equation then E=P\times \frac {I}{\pi r^{2}}

Given diameter of 0.259 cm= 0.00259 m and the radius will be half of it which is 0.001295 m

E=1.72\times 10^{-8}\times \frac {30}{\pi \times 0.001295^{2}}=9.79\times 10^{-2} N/c=0.0979 N/c

4 0
3 years ago
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