Answer:
Explanation:
Given
Airplane is flying with horizontally with a constant momentum during time interval
Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant
(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction
Answer:
The found acceleration in terms of h and t is:
Explanation:
(The complete question is given in the attached picture. We need to find the acceleration in terms of h and t in this question)
We are given 3 stages of movement of elevator. We'll first model them each of the stage one by one to find the height covered in each stage. After that we'll find the total height covered by adding heights covered in each stage, and equate it to Total height h. From that we can find the formula for acceleration.
<h3></h3><h3>Stage 1</h3>Constant acceleration, starts from rest.
Distance =
Velocity =
Constant velocity where
Velocity =
Distance =
<h3>Constant deceleration where
Velocity =
Distance =
Total height = y₁ + y₂ + y₃
Total height =
Find acceleration by rearranging the found equation of total height.
Total Height = h
h = 5a(t₁)²
