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kari74 [83]
3 years ago
6

BRAINLIEST!!! ❣

Chemistry
2 answers:
SOVA2 [1]3 years ago
8 0
Q1. A.

Q2. Nitrous oxide

Hope this helped ♥︎
mafiozo [28]3 years ago
6 0

Explanation:

the first question's answer is a

the second question's answer is c

You might be interested in
♡
Oksi-84 [34.3K]

Your question has been heard loud and clear.

Both scientific laws and scientific theories are not based on hypothesis.

Because , scientific laws are proven and so they are real not hypothetical.

Whereas scientifc theories can be hypothetical.

Thank you

4 0
3 years ago
PLEASE PLEASE HELP ME
Norma-Jean [14]

The high surface tension helps the paper clip - with much higher density - float on the water. The property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Basically it means that there is a sort of skin on the surface of water where the water molecules hold on tight together. If the conditions are right, they can hold tight enough to support your paper clip. The paperclip is not truly floating, it is being held up by the surface tension.

5 0
3 years ago
Read 2 more answers
For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
A cube made of an unknown material has a height of 9 cm. The mass of this cube is 3,645 grams.
kvasek [131]

Answer:

v=9*9*9=729 ml

3645/729= 5g/cm 3

8 0
3 years ago
How many particles are present in 10.0 moles of table salt?
Dima020 [189]

1.01 x 10^24 molecules.

Explanation:

To calculate the number of molecules in a given number of mole, we can simply multiply by Avogadro's number which is equal to 6.022 x 10 ^23.

Therefore,

10 molecules = 1.68 mol x (6.022 x 10^23 molecules) / (1 mol = 1.01 x 10^24) molecules.

I hope this helps :)

7 0
3 years ago
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