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guapka [62]
3 years ago
5

Ionic compounds are electrically overall thereofre the sum of

Chemistry
1 answer:
Setler79 [48]3 years ago
6 0
<span>substances consisting of ions held together by electrostatic attraction

</span>
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What happens to the matter in the body of an animal after it dies
sladkih [1.3K]
The matter will be consumed by other living organisms and the blood will settle to the bottom of the body
4 0
3 years ago
Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
HELP PLEASE (Solve this problem using the appropriate law). what is the volume of 0.382 moles of hydrogen gas at 1.50 atmosphere
kaheart [24]

Answer:

V = 6.17 L

Explanation:

Given data:

Volume = ?

Number of moles = 0.382 mol

Pressure = 1.50 atm

Temperature = 295 k

R = 0.0821 L. atm. /mol. k

Solution:

According to ideal gas equation:

PV= nRT

V = nRT/P

V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm

V = 9.252  L. atm.  / 1.50 atm

V = 6.17 L

5 0
3 years ago
1. How does protein substance in animal hide or skin be preserved from bacterial infection during tanning?
anyanavicka [17]

Answer:

1. By being cured

2. To remove the silica impurities from haemetite

3. The cathode will be bronze while the anode will be the silver

4. i) Wastes from industrial processes

ii) Waste waters and sewage

iii) Dumping of wastes into water bodies

5) Three methods to reduce air pollution includes

i) Promote the use of recycled of materials

ii) Promote and use renewable sources of energy

iii) Limit activities that involve the burning of fuels such as encouraging the use of mass transit buses, preventing the occurrence of fires in forests

Explanation:

1. In order to preserve the proteins in the hides of animal skin from putrefaction they are cured with salt to remove by, osmotic pressure difference,  the water content present in the animal hide

2. To remove the silica impurities from haemetite

The calcium oxide obtained from the decomposition of calcium carbonate undergoes a chemical reaction with the sand impurities in the mineral, haematite, to form calcium silicate or s l a g

3. Electroplating involves charging the metal to be electroplated negatively that is making it the cathode and placing it in an electrolytic cell that has a solution of the metal ions containing the metal salts

Therefore, the bronze medal to be plated with silver will be made the cathode while the silver from which we obtain the silver ions will be made the anode

4. Three causes of water pollution includes

Wastes from industrial processes

Waste waters and sewage

Dumping of wastes into water bodies

5.  The major causes of air pollution are the oxides produced from the combustion of fossil fuels such as sulfur dioxide, carbon dioxide, carbon monoxide as well as chemical gases from industrial processes.

8 0
3 years ago
What is the difference between a strong acid and a weak acid?
olasank [31]
The answer to this is C.
4 0
3 years ago
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