6th grade work help me please (:

Nitric acid, a major industrial and laboratory acid, is produced commercially by the multi-step Ostwald process, which begins wi

Marizza181 [45]

Answer: 3.178 Kg of ammonia must be used to produce 7.839 kg of nitric acid and The equations are not balanced. Explanation: Ostwald process is a multi-step for manufacturing Nitric Acid. First, We must check if our equations are balanced or not, by checking the amount of each element before and after the arrow. Step 1: NH3(g) + O2(g) ⟶ NO(g) + H2O(l) Step 2: NO(g) + O2(g) ⟶ NO2(g) Step 3: NO2(g) + H2O(l) ⟶ HNO3(l) + NO(g) For example in Step 1, the amount of Hydrogen atoms are different on both sides. On left side we can count 3 hydrogen atoms while on the right side we can count only 2 hydrogen atoms. In the Step 2, the amount of Oxygen atoms are different on both sides too. On the Left side we can count 3 oxygen atoms while on the right side we can count only 2 oxygen atoms and in step 3 the amount of Nitrogen atoms are different on both sides too. On the left side we can count 1 nitrogen atom while on the right side we can count 2 nitrogen atoms. So, Let´s balance equations by inspection, just adding coefficients to each compound, until the amount of atoms are equal on both sides. Step 1: 4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l) Step 2: 2NO(g) + O2(g) ⟶ 2NO2(g) Step 3: 3NO2(g) + H2O(l) ⟶ 2HNO3(l) + NO(g) Second we gather the information what we are going to use in our calculations. Final Mass of HNO3 = 7,839Kg and Molecular Weigth = 63,01g/mol NH3 Molecular Weight= 17,031 g/mol Third we start discoverying the amount of NH3 that reacted completed to generate 7,839Kg of HNO3, using the giving equation and its respective molecular weights. 7,839Kg of HNO3 x 1000g / 1Kg x 1mol HNO3 / 63,01g HNO3 x 3mol NO2 / 2 mol HNO3 x 2 mol NO/ 2 mol NO2 x 4 mol NH3/4 mol NO x 17,031g NH3/1 mol NH3 x 1 Kg / 1000g= 3,178 Kg NH3 The amount of NH3 that is required to produce 7,839 Kg of HNO3 is 3,178 Kg NH3

7 0

4 years ago

Help me please:

vovangra [49]

Answer:

24805.44 J

Explanation:

Step 1:

Data obtained from the question.

Mass (M) = 464g

Initial temperature (T1) = 120°C

Final temperature (T2) = 219°C

Change in temperature (ΔT) = T2 - T1 = 219°C - 120°C = 99°C

Specific heat capacity of lead (C) = 0.129cal/g°C = 4.184 x 0.129 = 0.54J/g°C

Heat (Q) =?

Step 2:

Determination of the heat Q, required the temperature of lead. This is illustrated below

Q = MCΔT

Q = 464 x 0.54 x 99

Q = 24805.44 J

Therefore, 24805.44 J of heat is required to raise the temperature of lead.

5 0

3 years ago

How many atoms are in lead ii bicarbonate

sertanlavr [38]

Answer:

11 atoms

Explanation:

The formula for lead(II) bicarbonate is: Pb(HCO3)2.

Atoms in Pb(HCO3)2:

Pb=1, H=1×2, C=1×2, O=3×2

1+1×2+1×2+3×2

=1+2+2+6

=11 atoms

4 0

4 years ago

For the reaction H2O(g) + Cl2O(g) → 2HCIO(9), you know S rxn and Sosys and S° of HCIO(g) and of H2O(g). Write an expression that

Liono4ka [1.6K]

The expression that can be used to determine Cl2O(g) is ;

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

<h3>Determine an expression that can be used to determine Cl2O(g)</h3>

The general expression for ΔS°rxn of a chemical reaction

ΔS°rxn = ∑mS°products - ∑nS°reactants

where ; m and n = stoichiometry coefficients

Considering the given reaction : H₂O(g) + Cl₂O(g) → 2HCIO (g)

$\beta$ S°rxn = $2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) } ^{o} - S_{Cl_{2}O } ^{o}$ ------- ( 2 )

Rearranging the equation above

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

Hence we can conclude that The expression that can be used to determine Cl2O(g) is ;

$S_{cl_{2}o(g) } ^{o} = 2S_{HCIO(g)} ^{o} - S_{H_{2}O(g) }^{o} - \beta S_{rxn} ^{o}$

Learn more about stoichiometry : brainly.com/question/16060223

3 0

2 years ago

4 Hydrogen has three naturally occurring isotopes. H.1, H-2, and H-3 The atomie mass of Hydrogen is 1.097 Which isotope is most

WINSTONCH [101]

Answer:

The number following the name of the element is the number of subatomic particles inside the nucleus of the atom. This means that it is the mass number of the isotope. The average atomic mass of the element is the sum of the products of the percentage abundance and mass number of the naturally occurring isotopes.

Since, the average atomic mass of the hydrogen is nearest to 1 then, the most abundant isotope should be hydrogen-1.

8 0

3 years ago