Question

Help fast. If 1500 joules of energy is used to heat 50g of water with a temperature of 20°C, then what will the final temperature be? (Water’s specific heat is 4.18 j/g°c)

Answer 1

50*f

Hope this helps

Answer 2

Answer:

27°C

Explanation:

q = 1500 J

m = 50g

c = 4.18 J/g°C

q = m·c·ΔT

ΔT = $\frac{1500J}{50g*4.18\frac{J}{gC} } = 7C$

ΔT = final temperature - initial temperature

Final temp = 20 + 7 = 27°C