Answer:
Xm ethylene glycol = 0.16
Molality = 10.75 m
Molarity = 11.3M
Explanation:
40.0% by mass. This data says that 40 g of ethyelen glycol are contained in 100 g of solution
Therefore: Mass of solute is 40g
Mass of solvent = 60 g
Mass of solution = 100 g
We convert the mass to moles → 40 g . 1mol / 62 g = 0.645 moles
We convert the solvent mass to moles → 60 g . 1mol /18g = 3.33 moles
Xm ethylene glycol = Moles of ethylene glycol / Total moles
0.645 / (0.645 + 3.33) = 0.16
Molality are the moles of solute in 1kg of solvent.
We convert the mass of solvent to kg → 60 g . 1kg/1000g = 0.060kg
Molality (mol/kg) = 0.645 mol /0.060kg = 10.75 m
To determine molarity we use the density of solution in order to find out the volume: density = mass / volume
1.75 g/cm³ = 100 g / volume → 100 g / 1.75 g/cm³ = 57.1 cm³ (1cm³ = 1ml)
We convert the solution's volume to L → 57.1 mL . 1L/1000mL = 0.0571L
Molarity → moles of solute in 1L of solution
Molarity (mol/L) → 0.645 mol / 0.0571L = 11.3M
