Answer:
Volume in L = 0.028 L
Explanation:
Given data:
Mass of copper phosphate = 27.6 g
Molarity solution = 6.03 M
Volume of solution = ?
Solution:
First of all we will calculate the number of moles of copper phosphate.
Number of moles = mass/molar mass
Number of moles = 27.6 g/ 159.61 g/mol
Number of moles = 0.17 mol
Volume of solution:
Molarity = number of moles / volume in L
By putting values,
6.03 M = 0.17 mol / volume in L
Volume in L = 0.17 mol / 6.03 M
Volume in L = 0.028 L
<span>ZnS + O --> ZnO + SO
Okay so first you have to count up the number of elements on each side of the equation. Your objective is to have the same number of each element on both sides.
Left Side:
Zn - 1
S - 1
O - 1
Right Side:
Zn - 1
S - 1
O - 2
Since there are two oxygens on the right side, you have to add a coefficient of 2 to the oxygen on the left side. The coefficient tells us that that element or molecule is being multiplied by the value of coefficient. Since we're adding a coefficient of 2 to the oxygen on the left side, there are now 2 oxygens on that side. Because that is the same amount of oxygen as on the right, the equation is now balanced.
Your final equation should look like this: </span>ZnS + 2O --> ZnO + SO
In conclusion, the answer is 2.