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elixir [45]
4 years ago
14

A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t

o answer the following questions. This reaction is...
endothermic.
exothermic.
Suppose 72.8g of HgO react. Will any heat be released or absorbed?
Yes, absorbed.
Yes, released.
No.
If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. kJ Round your answer to 3 significant digits. ×10
Chemistry
1 answer:
Leni [432]4 years ago
8 0

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

<em>The reaction is endothermic</em>

<em />

As the reaction is endothermic, when the reaction occurs,

<em>the heat is absorbed.</em>

<em></em>

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

<h3>3.06x10¹kJ are absorbed</h3>
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We have that every gas satisfies the fundamental gas equation, PV=nRT where P is the Pressure, V is the volume of the gas, n are the moles of the gas, R is a universal constant and T is the Temperature in Kelvin. We have that PV/T=nR and during our process, the moles of the gas do not change (no argon enters or escapes our sample). See attached.

6 0
4 years ago
The molar absorptivity of a tyrosine residue at 280 nm is 2000 M-1cm-1, while for tryptophan it is 5500 M-1cm-1. A protein has b
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Answer:

There are 4 tryptophans in the protein.

Explanation:

According to question,  protein contains one tyrosine residue and say x number of tryptophans.

Concentration of protein solution = 1.0 micromolar = 1.0\times 10^{-6} Molar

Molar absorptivity of a protein solution : \epsilon

\epsilon = \epsilon _{tyro}+\epsilon _{tryp}

=1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1}

Length of the cuvette = l = 1.0 cm

Absorbance of protein solution at 280 nm = A = 0.024

A=\epsilon \times l\times c ( Beer-Lambert's law)

0.024=(1\times 2000 M^{-1}cm^{-1}+x\times 5500 M^{-1}cm^{-1})\times 1 cm\times 1.0\times 10^{-6} M

Solving for x :

x = 4

There are 4 tryptophans in the protein.

7 0
3 years ago
An engineer that designs buildings is a (n)
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An architectural engineer.<span />
7 0
3 years ago
If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solutio
Dahasolnce [82]

Answer:

M_2=0.613M_1

Explanation:

M_1 = Concentration of stock solution

M_2 = Concentration of solution

V_1 = Volume of stock solution = 19 mL

V_2 = Volume of solution = 0.31 L= 310 mL

We have the relation

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1

\boldsymbol{\therefore M_2=0.613M_1}

The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.

6 0
3 years ago
A tank holds 6.90 m3 of water. What is the volume in ft3? (3.28 ft = 1 m, Remember significant figures, but this answer does not
AleksAgata [21]

Volume of tank = 6.9 m^{3} (given)

Since, 1 m = 3.28 ft

So,  

1 m^{3} = 35.287 ft^{3}

For 6.9 m^{3}:

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The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

243.4803 ft^{3} \simeq 243.5 ft^{3}

Hence, volume in ft^{3} is 243.5.

5 1
3 years ago
Read 2 more answers
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