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Harrizon [31]
3 years ago
8

Twenty five high school students complete a preparation program for taking the SAT test. Here are the SAT scores from the 25 stu

dents who completed the SAT prep program:
434 694 457 534 720 400 484 478 610 641 425 636 454


514 563 370 499 640 501 625 612 471 598 509 531


The mean of these scores is 536.00. We know that the population average for SAT scores is 500 with a standard deviation of 100.


The question is, are these students’ SAT scores significantly greater than a population mean of 500 with a population standard deviation of 100 ?


Note that the the maker of the SAT prep program claims that it will increase (and not decrease) your SAT score. So, you would be justified in conducting a one-directional test. (alpha = .05).
Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

the answer to the question is b

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What has a slope of 2/3
Angelina_Jolie [31]

Answer:

y = m x + b.23

Step-by-step explanation:

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4 years ago
-. A 6-foot-tall man is standing 50 feet from a flagpole. When he looks at the top of the flagpole,
taurus [48]

Answer:

The height of the flagpole is 46 feet

Step-by-step explanation:

First we find the ratio to connect the variables

Tan(∅) = opposite/adjacent

Plug in the Variables

Tan(39) = x/50

Solve for x

50*tan(39) = x

x = 40.48

Don't forget to include the man's height

40.48 + 6 = 46.48

7 0
3 years ago
Find the equation of line passing thorugh the point (5,7) and parellel line ,y=5x +4
Savatey [412]
The answer is 0 i hope i helped honey
3 0
3 years ago
How much will $850 amount to be in three years if it is invested at 8% interest compounded quarterly for 3 years? A. $886.47 B.
Dimas [21]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{compounded amount}\\
P=\textit{original amount deposited}\to &\$850\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, so four times}
\end{array}\to &4\\

t=years\to &3
\end{cases}
7 0
3 years ago
What is the strongest classification of the figure formed by the following points?
tatiyna

Answer:

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of \overline {AC} = The length of \overline {BD}

The length of \overline {AB} = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of \overline {CD} = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of \overline {AB} = The length of \overline {CD}

\overline {AC} is parallel to the horizontal axis

\overline {BD} is parallel to the horizontal axis

∴ \overline {AC} ║ \overline {BD}

Given that \overline {AB} = \overline {CD}, then \overline {AB} ║ \overline {CD}

Therefore, the quadrilateral ABCD is a parallelogram

(The angle ∠ABD = 180 - arctan (4/3) ≈ 126.9 > 90, therefore, the parallelogram ABCD is not a rectangle.)

6 0
3 years ago
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