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Ainat [17]
3 years ago
9

¿ ppr que no podemos automedicarnos ,cuando pensamos q tenemos el virus del CIVD-19?

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

Porque como tu no eres profesional en medicina, no sabes nada sobre las dosis de medicamentos ni de los efectos que pueden tener en tu cuerpo si se administran incorrectamente.

Explanation:

Es logico que solo vayas al medico para que te den la cura allí.

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1. A gas has a volume of 45 L at a pressure of 140 kPa. What is the volume when
pishuonlain [190]

Answer:

The new volume of the gas is 21 L.

Explanation:

Volume of a gas is inversely proportional to its pressure at constant temperature such that,

V\propto \dfrac{1}{P}

or

P_1V_1=P_2V_2

We have,

V_1=45\ L\\\\P_1=140\ kPa \\\\P_2=300\ kPa

It is required to find V₂. Using above law or Boyle's law such that :

V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{140\times 45}{300}\\\\V_2=21\ L

So, the new volume of the gas is 21 L.

7 0
3 years ago
What mass of salt (nacl) should you add to 1.48 l of water in an ice cream maker to make a solution that freezes at -13.4 ∘c ? a
blagie [28]
Answer is: mass of salt is 311,15 g.
V(H₂O) = 1,48 l · 1000 ml/l = 1480 ml.
m(H₂O) = 1480 g = 1,48 kg.
d(solution) = 1,00 g/ml.
ΔT(solution) = 13,4°C = 13,4 K.
Kf = 1,86 K·kg/mol; cryoscopic constant of water
i(NaCl) = 2; Van 't Hoff factor.
ΔT(solution) = Kf · b · i.
b(NaCl) = 13,4 K ÷ (1,86 K·kg/mol · 2).
b(NaCl) = 3,6 mol/kg.
n(NaCl) = 3,6 mol · 1,48 kg= 5,328 mol.
m(NaCl) = 5,328 mol · 58,4 g/mol = 311,15 g.

5 0
3 years ago
Read 2 more answers
How many oxygen molecules are required for glycolysis
morpeh [17]

Answer:

0

Explanation:

glycolysis requires no oxygen

6 0
3 years ago
Read 2 more answers
A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d
g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of Ba(OH)_2 as:-

Mass = 51.24 g

Molar mass of Ba(OH)_2 = 171.34 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{51.24\ g}{171.34\ g/mol}

Moles= 0.2991\ mol

Volume = 1.20 L

The expression for the molarity is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M

Thus,

Considering

Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

Molarity_{working\ solution}=0.100\ M

Volume_{working\ solution}=1\ L

Volume_{stock\ solution}=?

Molarity_{stock\ solution}=0.24925\ M

So,  

0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}

Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

6 0
3 years ago
How do you know a physical change has occurred when evaporating water produces gaseous water?
levacccp [35]

Answer:

Its b its the state not anything else

6 0
3 years ago
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