6.75 moles of H₂
Explanation:
We have the following balanced chemical reaction:
Mg + 2 HCl → MgCl₂ + H₂
From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.
Knowing this we devise the following reasoning:
if 2 moles of HCl produces 1 mole of H₂
then 13.5 moles of HCl produces X moles of H₂
X = (13.5 × 1) / 2 = 6.75 moles of H₂
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balancing chemical equations
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The answers are,
<u>B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.</u>
<u>C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.</u>
<u>E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.</u>
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Answer:
1.7 M
Explanation:
Given data:
Mass of AgNO₃ = 29.66 g
Volume of solution = 100 mL (100/1000 = 0.1 L)
Molarity of solution = ?
Solution;
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 29.66 g/ 169.87 g/mol
Number of moles = 0.17 mol
Molarity of solution:
Molarity = moles of solute / volume of solution in L
Molarity = 0.17 mol / 0.1 L
Molarity = 1.7 M
The answer will be 6CO2 + 6H2O ——-> 1 C6H12O6 + 6O2
Answer:
The correct answer is 29 grams.
Explanation:
Based on the given question, the reaction will be,
CH3CH=CHCH3 + H2 ⇒ CH3CH2CH2CH3
The molecular weight of butene is 56 grams per mole, and the molecular weight of butane is 58 grams per mole.
Thus, it can be said that 56 grams of butene reacts with hydrogen gas and produces 58 grams of butane.
Therefore, 28 grams of butene when reacts with hydrogen gas to give,
= 58/56 * 28 = 29 grams of butane.
Hence, the mass of butane produced will be 29 grams.
