Answer:
3. Inverse 1. Direct
Explanation:
P- pressure
V - volume
T - temperature
P1*V1 / T1 = P2*V2 / T2 ...... (1)
That's the general gas law with the combined ideas of charles, boyle & lussac.
Whenever you are restricted as "constant" temperature, volume, or pressure...cancel them off of your equation.
in this case 3. is indirectly telling us to cancel the temperature (T).
so we'll be left w P1*V1 = P2*V2
now notice that any relation ship that is multiplied like the one above consists of inversely related quantities. & so we conclude that-
P & V are inversely proportional or have an inverse relationship.
similarly in 1. we'll cancel p off of the general formula (1)
to be left with V1/T1 = V2/T2
also note that quantities involved in division are directly related to each other & hence the answer.
I believe the answer would be Neutrons
Ground state means 1s which can hold 2 electrons.
l for 1s is = 0
ml = 0 (given)
possible values of m = 0
so it can hold maximum of 2 electrons. One spin up and other spin down.
Missing in your question :
Ksp of(CaCO3)= 4.5 x 10 -9
Ka1 for (H2CO3) = 4.7 x 10^-7
Ka2 for (H2CO3) = 5.6 x 10 ^-11
1) equation 1 for Ksp = 4.5 x 10^-9
CaCO3(s)→ Ca +2(aq) + CO3-2(aq)
2) equation 2 for Ka1 = 4.7 x 10^-7
H2CO3 + H2O → HCO3- + H3O+
3) equation 3 for Ka2 = 5.6 x 10^-11
HCO3-(aq) + H2O(l) → CO3-2 (aq) + H3O+(aq)
so, form equation 1& 2&3 we can get the overall equation:
CaCO3(s) + H+(aq) → Ca2+(aq) + HCO3-(aq)
note: you could get the overall equation by adding equation 1 to the inverse of equation 3 as the following:
when the inverse of equation 3 is :
CO3-2 (aq) + H3O+ (aq) ↔ HCO3- (aq) + H2O(l) Ka2^-1 = 1.79 x 10^10
when we add it to equation 1
CaCO3(s) ↔ Ca2+(aq) + CO3-2(aq) Ksp = 4.5 x 10^-9
∴ the overall equation will be as we have mentioned before:
when H3O+ = H+
CaCO3(s) + H+(aq) ↔ Ca2+ (aq) + HCO3-(aq) K= 80.55
from the overall equation:
∴K = [Ca2+][HCO3-] / [H+]
when we have [Ca2+] = [HCO3-] so we can assume both = X
∴K = X^2 / [H+]
when we have the PH = 5.6 so we can get [H+]
PH = - ㏒[H+]
5.6 = -㏒[H]
∴[H] = 2.5 x 10^-6
so, by substitution on K expression:
∴ 80.55 = X^2 / (2.5 x10^-6)
∴X = 0.0142
∴[Ca2+] = X = 0.0142
The molar mass of the M2O = 2(molar mass of M) + molar mass of oxygen
Molar mass of oxygen = 16
Therefore:
231.74 = 2(molar mass of M) + 16
215.74 = 2*molar mass of M
molar mass of M = 107.87 grams
Now, from the given formula, we can notice that the metal M is monovalnet and we know that chlorine is monovalent as well.
Therefore, the compound formed will be: MCl
molar mass of chlorine = 35.5 grams
Therefore,
molar mass of MCl = 107.87 + 35.5 = 143.37 grams
