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3 years ago

How many ions are present in iron 2 oxide

1 answer:

8 0

Iron(II) oxide also refers to a family of related non-stoichiometric compounds, which are typically iron deficient with compositions ranging from Fe0.84O to Fe0.95O.

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Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).

Zinaida [17]

Answer:

0.01185M = moles/0.02755L

0.02755*0.01185=0.00032647

Explanation:

7 0

3 years ago

(-5)+(+7)-(-4) + (+12) A 8 B 10 C 18 d 20

Vladimir79 [104]

Answer:

C-18

Explanation:

Step one follow order of operations

Add and subtract from left to right(-5)+(7)=2-(-4)+(12)

STEP 2

Apply negative Rule -(-4)=+4=2+4+(12)

then add 2+4+12=18

5 0

3 years ago

Write the chemical formula for the anion present in the aqueous solution of Pb(C2H3O2)2

yKpoI14uk [10]

Pb(C₂H₃O₂)₂ is lead(II) acetate

Pb(C₂H₃O₂)₂ --> Pb²⁺ + C₂H₃O₂²⁻

Lead(II) acetate ionizes in aqueous solution to form lead cation and acetate anion.

The chemical formula for the anion present in the aqueous solution of Pb(C₂H₃O₂)₂ is C₂H₃O₂²⁻

C₂H₃O₂²⁻ or CH₃COO⁻ is called the acetate ion.

Therefore, the correct answer is C₂H₃O₂²⁻

3 0

3 years ago

Read 2 more answers

Which of the following is not included in John Dalton's modern theory of the atom?

Akimi4 [234]

The answer for the following question is option "C".

Option C is not included in the John Dalton's modern theory of an atom.

"It states atoms of different elements combine to form new compound" but not new elements

Explanation:

According to John's Dalton's modern theory of an atom:

1. All matter is composed of atoms.

2. Atoms cannot be created,destroyed or subdivided in the ordinary chemical reactions.

3. Atoms of one element differ in the properties from atoms of an another element.

(i.e.)Each and every atom of the element has its own unique properties of their own.

4. Atoms of one element combine with the atoms of another element to form new compound.

5. Atoms that make up an element are identical to each other.

7 0

3 years ago

In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z

storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0

3 years ago