Answer:
3.29 × 10²⁸ Atoms
Solution:
Moles and Number of atoms are related to each other as,
Moles = Number of Atoms / 6.022 × 10²³ ------- (1)
Data Given;
Moles = 5.472 ×10⁴
Number of Atoms = ?
Solving eq. 1 for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³
Putting values,
Number of Atoms = 5.472 ×10⁴ mol × 6.022 × 10²³ atoms.mol⁻¹
Number of Atoms = 3.29 × 10²⁸ Atoms
Answer:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Explanation:
In a <em>solubility table</em> you find:
- AgNO₃ (silver nitrate) is highly soluble
- KCl (potassium chloride) is soluble
- AgCl (silver chloride) is insoluble
- KNO₃ (potassium nitrate) is soluble
In a chemical equation the states of soluble compounds is identified as aqeous, using the letter "aq" in parenthesis, and the state of insoluble compounds is identified as solid, using "s" in parenthesis.
Then, the reaction showing the states of the reactants and products is:
- AgNO₃ (aq) + KCl (aq) → AgCl (s) + KNO₃ (aq)
Answer:
Zero to the power of zero, denoted by 00, is a mathematical expression with no agreed-upon value. The most common possibilities are 1 or leaving the expression undefined, with justifications existing for each, depending on context
Explanation:
<u>Answer:</u> The 
of the reaction at given temperature is -12.964 kJ/mol.
<u>Explanation:</u>
For the given chemical reaction:
The expression of 
for the given reaction:
We are given:
Putting values in above equation, we get:
To calculate the Gibbs free energy of the reaction, we use the equation:
where,
= Gibbs' free energy of the reaction = ?
= Standard gibbs' free energy change of the reaction = 0 J (at equilibrium)
R = Gas constant = 
T = Temperature = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
= equilibrium constant in terms of partial pressure = 
Putting values in above equation, we get:
Hence, the of the reaction at given temperature is -12.964 kJ/mol.
Freezing Point of Sea water would be lower than that of Pure Water. It is because of salinity of the water
Hope this helps!
