1 mole of NH42SO4 contains 42 moles of H. We take the 42 moles of H and multiply that times Avogadro's number (6.02x10^23) and get 2.5284x10^25 atoms of hydrogen
Answer:
Q = -897 kJ/mol
Explanation:
From the given information:
The heat released Q = -65.9 kJ
To start with the molar mass of 
= 2 × (molar mass of H) + 2 × (molar mass of O)
= (2 × 1.008) + (2 × 16.0 )
= 34.016 g/mol
However, given that:
mass of 2.50 g
The number of moles of = 
Finally; Using the formula:
Q = -897 kJ/mol
The minimum energy required to remove an electron from a potassium metal can be obtained by subtracting the energy of the incident photons from the kinetic energy of the removed photoelectrons. Based from the given values, the following equation is obtained:
Minimum energy required = 4.23×10^-19 J - <span>1.864×10^-21 J
</span>
We then get 4.2114 x 10^-19 J as the minimum energy required to remove the electron. We then convert this into units of energy per mole. This is to be done by using Avogadro's number which result to the following equation:
Minimum energy required per mole = 4.2114 x 10^-19 J x 6.022 x 10^23 mol^-1
The final answer is then 253.608 kJ/mol
The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.
