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2 years ago

Which molecule could form a coordinate covalent bond with a proton (h )?

Chemistry

2 answers:

Luda [366]2 years ago

8 0

Answer:

A chlorine (Cl-) molecule could make a coordinated covalent bond with a proton (H +, in this case) forming hydrogen chloride (HCl).

Explanation:

Covalent bonds occur when there is electron sharing between atoms, making all atoms that participate in this type of bond stable, but in the case of coordinated or dative covalent bond, the atom that has available pairs of electrons and is not performing Sharing them with another atom can “donate” these free electrons to any other atom, thereby performing a simple covalent bond and a coordinated or dative covalent bond, where electron (s) transfer from one atom to the other. This type of chemical bond is quite common and often occurs with chlorine, sulfur, phosphorus, among other various chemical elements. As an example we can cite the bond between chlorine and hydrogen to form hydrogen chloride.

For a coordinated covalent bond to occur it is necessary for one of the atoms to share a pair of electrons with another atom, and at the same time assign one or more electrons to another atom, which only participates in the bond receiving the electrons.

Reil [10]2 years ago

5 0

Molecule is the smallest particle of a compound or an element with similar properties as the element or the compound. Covalent bond (dative bond) is a bond that is formed due to the sharing of electrons between atoms. Coordinate covalent bond is a type of covalent where electrons shared during bond formation comes from one atom. In this case a molecule of H2O would form a coordinate bond with H+ because the oxygen contains a lone pair of electrons forming H3O+.

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Alchen [17]

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<h3>Explanation</h3>

Helium is a noble gas. The interaction between two helium molecules is rather weak, which makes the gas rather "ideal."

Consider the ideal gas law:

$P\cdot V = n\cdot R\cdot T$ ,

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of gas particles in the gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas in degrees Kelvins.

The question is asking for the final volume $V$ of the gas. Rearrange the ideal gas equation for volume:

$V = \dfrac{n \cdot R \cdot T}{P}$ .

Both the temperature of the gas, $T$ , and the pressure on the gas changed in this process. To find the new volume of the gas, change one variable at a time.

Start with the absolute temperature of the gas:

$T_0 = (32.0 + 273.15) \;\text{K} = 305.15\;\text{K}$ ,
$T_1 = (-14.5 + 273.15) \;\text{K} = 258.65\;\text{K}$ .

The volume of the gas is proportional to its temperature if both $n$ and $P$ stay constant.

$n$ won't change unless the balloon leaks, and
consider $P$ to be constant, for calculations that include $T$ .

$V_1 = V_0 \cdot \dfrac{T_1}{T_2} = 5.57\times 10^{4}\;\text{L}\times \dfrac{258.65\;\textbf{K}}{305.15\;\textbf{K}} = 4.72122\times 10^{4}\;\text{L}$ .

Now, keep the temperature at $T_1 =258.65\;\text{K}$ and change the pressure on the gas:

$P_1 = 0.995\;\text{atm}$ ,
$P_2 = 0.720\;\text{atm}$ .

The volume of the gas is proportional to the reciprocal of its absolute temperature $\dfrac{1}{T}$ if both $n$ and $T$ stays constant. In other words,

$V_2 = V_1 \cdot\dfrac{\dfrac{1}{P_2}}{\dfrac{1}{P_1}} = V_1\cdot\dfrac{P_1}{P_2} = 4.72122\times 10^{4}\;\text{L}\times\dfrac{0.995\;\text{atm}}{0.720\;\text{atm}}=6.52\times 10^{4}\;\text{L}$

(3 sig. fig. as in the question.).

See if you get the same result if you hold $T$ constant, change $P$ , and then move on to change $T$ .

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jeka57 [31]

Answer:

<u><em>To protect your hands from sharp items and broken glassware and reduce while washing glassware.</em></u>

Hope this helped! :)

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