Answer:
3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)
Explanation:
your question is not completed , perhaps the question is similar to this solution, you can use it .
The balanced equation is
3 Fe (s) + 4 H2O (l) -----> Fe3O4 (s) + 4 H2 (g)
Explanation: In order to balance an equation we must ensure that the number of atoms of each species on right side of the arrow must be equal to the number of atoms of each species on left side of the arrow.
The ore contains 55.4% calcium phosphate (related to the mineral apatite) so the amount of Ca3(PO4)2 is 55.4%x=1000g so x=1000/0.554= 1.805kg. Now for the % of P in this amount of calcium phosphate, use all the masses of the elements in Ca3PO4= Ca=40.078 x 3= 120.23 and (PO4)2= (30.974+64)2=189.95 (NB oxygen is 16 mass x 4 =64) so the total mass is 310.2 and we have 61.95 of P (Pmass x 2) so 61.95/3102.= 0.19 or 19% P. So of the 1.805 x 0.19= 0.34kg of phosphorus.
Answer:
0.15 L
Explanation:
You need to first find the volume of the container. You can do this by dividing the mass by the density. This will give you the mass in mL.
5.00 kg = 5,000 g
(5,000 g)/(1.00 g/mL) = 5,000 mL
5,000 mL = 5 L
Now, find the volume the seawater will take up.
(5,000 g)(1.03 g/mL) = 4854.4 mL
4854.4 mL = 4.85 L
Subtract the two volumes to find the volume that left unfilled.
5 L - 4.85 L = 0.15 L
The answer is theory because it says if and that means theory