All categories

3 years ago

Please solve (2×3^3)-(-9-5)^2=

Mathematics

1 answer:

-Dominant- [34]3 years ago

7 0

Answer:

Step-by-step explanation:

Power: 3 ^ 3 = 27

Multiple: 2 * 27 = 54

Subtract: -9 - 5 = -14

Power: (-14) ^ 2 = 196

Subtract: 54 - 196 = -142

Compare: = (-142)

You might be interested in

Sixth grade

garri49 [273]

Answer:

11-C

Step-by-step explanation:

Cause 11-C

equels the same amount as the one on the top of 11-C

6 0

3 years ago

Help help help help help PLEASE

Alinara [238K]

A. 0,0 1,14. It is showing that it’s a positive correlation
B. I think 120

4 0

3 years ago

Read 2 more answers

Help please due today.

BARSIC [14]

Answer:

A) $\frac{7}{tan55^\circ}$

Step-by-step explanation:

$tan\theta=\frac{opposite}{adjacent}\\ \\tan55^\circ=\frac{7}{BC}\\ \\BC*tan55^\circ=7\\\\BC=\frac{7}{tan55^\circ}$

5 0

3 years ago

What is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?

3241004551 [841]

Rewrite the given equation in slope intercept form:

5 y = 10 – 2 x

y = - 0.4 x + 2

Since the two lines are parallel, therefore they have similar slope which is – 0.4, so the equation is:

y = - 0.4 x + b

Given that x = 5, y = -4, find for b:

-4 = - 0.4 (5) + b

b = -2

So the answer is:

y = - 0.4 x – 2

7 0

4 years ago

The ratio of girls to boys in Liza’s classroom is 5 to 4. How many girls are in her classroom if there is a total of 27 students

Soloha48 [4]

Answer:

$\boxed{\sf Number \ of \ girls \ in \ classroom =15}$

Given:

Ratio of numbers of girls to boys = 5:4

Total number of students = 27

To Find:

Numbers of girls in classroom

Step-by-step explanation:

Let number of girls be 'x' and number of boys be 'y'

$\sf \implies \frac{x}{y} = \frac{5}{4} \ \ \ \ \ \ \ \ \ \ .....Eq_{1} \\ \\ \sf \implies x + y = 27 \ \ \ \ \ \ \ \ \ \ .....Eq_{2}$

$\sf \bold{ \large From \ Eq_{1} :} \\ \sf \implies \frac{x}{y} = \frac{5}{4} \\ \\ \sf Taking \: the \: reciprocal \: of \: both \: sides:\\ \sf \implies \frac{y}{x} = \frac{4}{5} \\ \\ \sf Multiply \: both \: sides \: by \: x: \\ \sf \implies y = \frac{4}{5} x$

$\sf \bold{ \large Substituting \ value \ of \ y \ in \ Eq_{2},} \\ \bold{ \large we \ get:} \\ \sf \implies x + \frac{4}{5} x = 27 \\ \\ \sf Put \: each \: term \: in \: x + \frac{4}{5} x \: over \: the \: common \\ \sf denominator \: 5: \\ \sf \implies \frac{5x}{5} + \frac{4x}{5} = 27 \\ \\ \sf \frac{5x}{5} + \frac{4x}{5} = \frac{5x + 4x}{5}: \\ \sf \implies \boxed{ \sf \frac{5x + 4x}{5}} = 27 \\ \\ \sf 5x + 4x = 9x : \\ \sf \implies \frac{ \boxed{ \sf 9x}}{5} = 27 \\ \\ \sf Multiply \: both \: sides \: of \: \frac{9x}{5} = 27 \: by \: \frac{5}{9} : \\ \sf \implies \frac{9x}{5} \times \boxed{\frac{5}{9}} = 27 \times \boxed{ \frac{5}{9} } \\ \\ \sf \frac{ \cancel{9} \times \cancel{5}}{ \cancel{5} \times \cancel{9}} x = x : \\ \sf \implies \boxed{x} = 27 \times \frac{5}{9} \\ \\ \sf 3 \times \cancel{9} \times \frac{5}{ \cancel{9}} = 5 \times 3 : \\ \sf \implies x = \boxed{5 \times 3} \\ \\ \sf 5 \times 3 = 15 : \\ \sf \implies x = 15$

So,

Numbers of girls in classroom = 15

6 0

4 years ago

Please solve (2×3^3)-(-9-5)^2= ​

Please solve (2×3^3)-(-9-5)^2=