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3 years ago

Write an equation that describes each line in slope intercept form........slope= 4 y-intercept=-3

Mathematics

2 answers:

LenaWriter [7]3 years ago

7 0

I’m pretty sure it’s y=4x-3

mario62 [17]3 years ago

4 0

Answer:

y = 4x - 3

Step-by-step explanation:

slope - intercept form is: y = m*x + b, where m is slope and b is the y intercept.

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Does anyone know the answer to this!?

PolarNik [594]

Answer:

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

Step-by-step explanation:

You can use these Cramer's formulas to solve for x and y:

$x=\dfrac{|A_x|}{|A|},\\ \\y=\dfrac{|A_y|}{|A|},$

where

$|A|=\left|\begin{array}{cc}12&-13\\ \\17&-22\end{array}\right|\\ \\ \\|A_x|=\left|\begin{array}{cc}7&-13\\ \\-51&-22\end{array}\right|\\ \\ \\|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

So,

$|A_y|=\left|\begin{array}{cc}12&7\\ \\17&-51\end{array}\right|$

4 0

3 years ago

Each of the 25 students in Mr. McDonald’s class sold 16 raffle tickets. If each ticket costs $15, how much money did Mr. McDonal

REY [17]

So do
25x16=400
this shows how many raffle tickets were sold all together
Then do 400x$15 =$6000
So all together they raised $6000

6 0

3 years ago

Read 2 more answers

Triangle ABC has A(-3,6),B(2,1), and C(9,5) what the length of side AB? What the length BC what the length AC and what ABC

vovikov84 [41]

Answer:

AB = 5√2

AC = √145

BC = √65

Step-by-step explanation:

Using the formula for calculating the distance between two points

D = √(x2-x1)²+(y2-y1)²

For AB A(-3,6),B(2,1),

AB = √(2+3)²+(1-6)²

AB = √(5)²+(-5)²

AB = √25+25

AB = √50

AB = 5√2

For AC A(-3,6) and C(9,5)

AC = √(9+3)²+(5-6)²

AC = √(12)²+(-1)²

AC = √144+1

AC = √145

For BC B(2,1), and C(9,5)

BC = √(9-2)²+(5-1)²

BC = √(7)²+(4)²

BC = √49+16

BC = √65

Since All the sides are difference, hence triangle ABC is a scalene triangle

8 0

3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

3 years ago

Solve 250 ÷ 5 ÷ 10 making sure to divide in the proper order.

attashe74 [19]

Your answer would be 5.

3 0

3 years ago

Read 2 more answers