Answer:
$21.75
Step-by-step explanation:
It says he spent his earnings on lunch.
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ ≥ 50000
For the alternative hypothesis,
µ < 50000
Since the population standard deviation is given, z score would be determined from the normal distribution table. The formula is
z = (x - µ)/(σ/√n)
Where
x = lifetime of the tyres
µ = mean lifetime
σ = standard deviation
n = number of samples
From the information given,
µ = 50000 miles
x = 45800 miles
σ = 8000
n = 29
z = (50000 - 45800)/(8000/√29) = - 2.83
Looking at the normal distribution table, the probability corresponding to the z score is 0.9977
Since alpha, 0.05 < than the p value, 0.9977, then we would accept the null hypothesis. Therefore, At a 5% level of significance, the data is not highly consistent with the claim.
Answer:
C) About $85
Step-by-step explanation:
Please consider the complete question.
Carl puts $1.10 in his penny bank every day in the month of July (31 days). His total saving at the end of June is $55.00. What is the best estimate at the end of July?
A) about $25
B) about $115
C) about $85
D) about $66
First of all, we will round $1.10 to nearest whole number and round 31 to nearest tens as:
So amount saved in 30 days would be 30 times $1.
Carl's savings at the end of July would be amount saved in June plus amount saved in July that is 
Therefore, the estimate for Carl's saving at the end of July is $85 and option C is the correct choice.
Answer: 98
Step-by-step explanation:
The answer to this question is:
13.5
