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LiRa [457]
3 years ago
11

If p and q are distinct primes. Find the number of positive divisors of p^2 * q^2

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
8 0

Answer:

The number of positive divisors are 7.

Step-by-step explanation:

Since it is given that p and q are prime numbers thus they will not have any divisors other that itself and 1

The number p^{2}\times q^{2} can be represented as

p^{2}\times q^{2}=p\times (p\times q^{2})\\p^{2}\times q^{2}=(p\times q)\times (p\times q)\\p^{2}\times q^{2}=(p^{2}\times q)\times q\\

Thus the number (pq)^{2} can be divided by:

1) 1

2) p

3) q

4) pq

5)p\times q^{2}

6)p^{2}\times q

7)(pq)^{2}

Thus the number of positive divisors are 7.

kkurt [141]3 years ago
3 0

Answer:

9

Step-by-step explanation:

We know that for p^mq^n  where p and q are different prime numbers the number of positive divisors are (m+1) (n+!)

We have given p^2q^2

So here m=2 and n=2

So number of positive divisors =(2+1)\times (2+1) =9

So the number of positive divisors of  p^2q^2 is 9

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ANSWER = A.



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