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astra-53 [7]
3 years ago
7

What is slope and how do you find it??

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

the formula for slope is

\frac{(y2-y1)}{(x2-x1)}

so just replace y and x for the proper values

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Read 2 more answers
1. A line segment has endpoints of Y(2,-3) and Z(-6,-1).
Orlov [11]

The answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

What is slope of a line segment ?

The ratio of the difference in y-coordinates over the equivalent x-coordinates between two different locations on a line.

It is given that a line segment has endpoints of Y(2,-3) and Z(-6,-1).

Let's solve the given parts based on the above data.

a.

The length of the line segment will be given by :

YZ = \sqrt({x_{2} - x_{1})^2 + (y_{2}- y_{1})^2}

YZ = √ [( -6 -(2)]^2 + [ -1 - (-3)]^2}

YZ = √ (-8)² + 2²)

YZ = √68

YZ = 8.24 units

b.

The midpoint (say M) of the line segment will be given by :

M = ( \frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2})

M = [(2-6)/2 , (-3-1)/2]

M = ( -2 , -2 )

c.

And the equation of line passing through points Y and Z will be :

y_{2} - y_{1} = m ( x_{2} - x_{1} )

Let's calculate value of slope (m) firstly which will be :

m =(y_{2} - y_{1}) / ( x_{2} - x_{1} )

m = ( -1 + 3 ) / (-6 - 2)

m = 2 / -8

m = -1 / 4

or

m = -0.25

Using the value of slope (m) : we get the equation of line as :

y - y_{1} = - 0.25 ( x - x_{1} )

or

(y + 3) = - 0.25 ( x - 2)

y + 3 = -0.25 x + 0.50

or

y + 0.25 x - 2.5 = 0

If we multiply by 4 throughout the equation ; then the equation of line can also be written as :

4y + x - 10 = 0

Therefore the answers will be :

a. The length of the line segment will be equal to 8.24 units.

b. The midpoint of the line segment will be ( -2 , -2 ).

c. The equation of line passing through points Y and Z will be 4y + x - 10 = 0

Learn more about line segment here ;

brainly.com/question/23629348

#SPJ1

5 0
1 year ago
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