TRUE. When you approach a yield sign, while trying to enter or merge onto another road, traffic already on that road has the right of way.
Answer:Velocity can be represented by an arrow, with the length of the arrow representing speed and the way the arrow points representing direction. Objects have the same velocity only if they are moving at the same speed and in the same direction. ... The SI unit for velocity is m/s, plus the direction the object is traveling.
ANSWER
T₂ = 10.19N
EXPLANATION
Given:
• The mass of the ball, m = 1.8kg
First, we draw the forces acting on the ball, adding the vertical and horizontal components of each one,
In this position, the ball is at rest, so, by Newton's second law of motion, for each direction we have,
![\begin{gathered} T_{1y}-F_g=0_{}_{}_{} \\ T_2-T_{1x}=0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T_%7B1y%7D-F_g%3D0_%7B%7D_%7B%7D_%7B%7D%20%5C%5C%20T_2-T_%7B1x%7D%3D0%20%5Cend%7Bgathered%7D)
The components of the tension of the first string can be found considering that they form a right triangle, where the vector of the tension is the hypotenuse,
![\begin{gathered} T_{1y}=T_1\cdot\cos 30\degree \\ T_{1x}=T_1\cdot\sin 30\degree \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20T_%7B1y%7D%3DT_1%5Ccdot%5Ccos%2030%5Cdegree%20%5C%5C%20T_%7B1x%7D%3DT_1%5Ccdot%5Csin%2030%5Cdegree%20%5Cend%7Bgathered%7D)
We have to find the tension in the horizontal string, T₂, but first, we have to find the tension 1 using the first equation,
![T_1\cos 30\degree-m\cdot g=0](https://tex.z-dn.net/?f=T_1%5Ccos%2030%5Cdegree-m%5Ccdot%20g%3D0)
Solve for T₁,
![T_1=\frac{m\cdot g}{\cos30\degree}=\frac{1.8kg\cdot9.8m/s^2}{\cos 30\degree}\approx20.37N](https://tex.z-dn.net/?f=T_1%3D%5Cfrac%7Bm%5Ccdot%20g%7D%7B%5Ccos30%5Cdegree%7D%3D%5Cfrac%7B1.8kg%5Ccdot9.8m%2Fs%5E2%7D%7B%5Ccos%2030%5Cdegree%7D%5Capprox20.37N)
Now, we use the second equation to find the tension in the horizontal string,
![T_2-T_1\sin 30\degree=0](https://tex.z-dn.net/?f=T_2-T_1%5Csin%2030%5Cdegree%3D0)
Solve for T₂,
![T_2=T_1\sin 30\degree=20.37N\cdot\sin 30\degree\approx10.19N](https://tex.z-dn.net/?f=T_2%3DT_1%5Csin%2030%5Cdegree%3D20.37N%5Ccdot%5Csin%2030%5Cdegree%5Capprox10.19N)
Hence, the tension in the horizontal string is 10.19N, rounded to the nearest hundredth.
Answer:
Newton believed that mass tells gravity how much force to exert. Einstein believed that mass tells space-time how to curve.
Explanation:
Isaac Newton believed that bodies on earth had a force of gravity pulling them down as a result of their masses.
Albert Einstein believed that the bodies were not pulled down but were moving around in a circular sphere/manner.
This confirms Newton believing that mass tells gravity how much force to exert and Einstein believing that mass tells space-time how to curve.
The amount of charge that passes per unit time is called <em>electric current</em> .
Current has dimensions of [Charge] / [Time] .
It's measured and described in units of ' Ampere ' .
1 Ampere means 1 Coulomb of charge passing a point every second.