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3 years ago

Select the correct arrows. Identify the arrows that show the correct direction of heat transfer.

Physics

2 answers:

ohaa [14]3 years ago

4 0

Answer: Is there suppose to be a picture?

Explanation:

ASHA 777 [7]3 years ago

4 0

Mmmmm is there a picture???

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A transformer has a 240 V primary and a 60 V secondary. With a 5 ohm load connected, what is the primary current?

musickatia [10]

Answer:primary current is 3A

Explanation:

primary voltage Vp=240V

secondary voltage Vs=60V

resistance 5Ω

primary current in the circuit is

$I_{P} =I_{S} \frac{V_{S}}{V_{P}}\\I_{P} =\frac{V_{S}}{R} \frac{V_{S}}{V_{P}}\\I_{P}=\frac{60\times 60}{5\times 240\\}\\I_{P}=3 A$

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3 years ago

To be a healthy family, which of the statements below is TRUE:

Ipatiy [6.2K]

Answer:

wait what do u mean by healthy beccause i choose C

Explanation:

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3 years ago

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_____ can alter wind flow and create a rain shadow effect. Beaches Lakes Mountains Oceans

Ket [755]

The correct answer is Mountains. Mountains can alter wind flow and create a rain shadow effect. A mountain is a large landform and is high surrounding a limited area. It is generally steeper and higher than a hill.

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3 years ago

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Red light is bent the least of all colors as it passes through a prism. What does this tell you about red light? It has a short

Alik [6]

Answer:

Longest wavelength, lowest intensity

Explanation:

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3 years ago

Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the

Doss [256]

Answer:

$v_{su} = 19.44 m/s$

Explanation:

$m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg$

$T=9.29x10^8\\r_{o}=1.43x10^{12}$

If the sun considered as x=0 on the axis to put the center of the mass as a:

$m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}$

solve to r1

$r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}$

$r_1=1.428x10^9m$

Now convert to coordinates centered on the center of mass. call the new coordinates x' and y' (we won't need y'). Now since in the sun centered coordinates the angular momentum was

$L = \frac{m_{sa}*2*pi*r_1^2}{T}$