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Papessa [141]
3 years ago
9

How do you do this problem?

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Production by Mexico is the same percentage (3%) of world production for the years of interest, so the relation is

... (mexico production) = 0.03 × (world production)

Then, dividing by 0.03, we get

... (mexico production)/0.03 = (world production)

The change in world production is the difference between the amounts for the two years, so is

... (production increase) = (2007 world production) - (2000 world production)

... = 24/0.03 - 18/0.03 = (24 - 18)/0.03

... = 6/0.03 = 200 . . . . million metric tons

The appropriate choice is (D) 200.

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What are the factors of 36?
denis23 [38]

Answer:

1, 2, 3, 4, 6, 9, 12, 18, 36

Step-by-step explanation:

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2 years ago
In how many ways can six people sit in a six-passenger car?
nekit [7.7K]

Answer:

number of ways = 720

Step-by-step explanation:

The number of ways  six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then

number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720

Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.

5 0
3 years ago
A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects
Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let <em>X</em> denote the number of green candies.

The probability of green candies is, <em>p</em> = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, <em>n</em> = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

                                       = 0.17228 + 0.17946 + 0.15328

                                       = 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

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Answer: The correct answer is (B)

Step-by-step explanation: No. Ari should have written the percent ratio as 5/100

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