Answer:
Cotton, polyester, and pima
Explanation:
Answer:
a) The mass of lead in the alloy = 0.28 kg
b) There can be dissolved 1.46 kg more of lead.
Explanation:
Step 1: Data given
mass of the magnesium-lead alloy = 5.5 kg
200 °C → 5 wt% Pb
350 °C → 25 wt% Pb
a) What mass of lead is in the alloy?
We have to calculate (for the magnesium-lead alloy) the mass of lead in 5.5 kg of the solid α phase at 200°C just below the solubility limit. The solubility limit for the α phase at 200°C is about 5 wt% Pb.
The mass of lead in the alloy = (0.05)*(5.5 kg) = 0.28 kg
b) If the alloy is heated to 350°C, how much more lead may be dissolved in the α phase without exceeding the solubility limit of this phase?
At 350°C, the solubility limit of the a phase increases to approximately 25 wt% Pb.
C(lead) = ((mass fo lead in alloy) + (mass lead)) / ((magnesium-lead alloy mass) + (mass lead))
0.25 = (0.28 + m(Pb)) / ( 5.5 + m(Pb))
0.25 * ( 5.5 + m(Pb)) = (0.28 + m(Pb))
1.375 + 0.25 m(Pb) = 0.28 + m(Pb)
1.095 = 0.75 m(Pb)
m(Pb) = 1.095 / 0.75
m(Pb) = 1.46
There can be dissolved 1.46 kg more of lead.
Answer:
14.68 oz
Explanation:
The mean volume is the average volume of all the regular soda cans put together; 14.5 oz. The standard deviation 0.18 oz is the maximum deviation from the mean. It can be 14.5-0.18= 14.32 oz which is the usual minimum or 14.5 + 0.18=14.68 oz which is the usual maximum
Answer:
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Explanation:
<em>Glucose and galactose are monosaccharides that differ from one another only at position C-4. Thus, they are epimers that have an identical configuration in all the positions except in position C-4. ... Glucose and galactose are epimers that do not differ in position C-5 but differ in position C-4.</em>
Answer:
8m/min
Explanation:
120 m / 15 min = 8 meters per min