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MrRissso [65]
3 years ago
14

How much heat (in kJ) would need to be removed to cool 150.3 g of water from 25.60°C to -10.70°C?

Chemistry
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

Q = -22.9 kJ

Explanation:

Given that,

Mass of water, m = 150.3 g

Water gets cool from 25.60°C to -10.70°C.

The specific heat of water, c = 4.2 J/g°C

The formula for heat needed is given by :

Q=mc\Delta T\\\\Q=150.3\times 4.2 \times (-10.7-25.6)\\\\Q=-22914.738\\\\or\\\\Q=22.9\ kJ

So, 22.9 kJ of heat is needed to be removed to cool.

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How many nickel atoms are contained in a 92.02 mole sample
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How many total atoms are in 0.680 g of P₂O5?
Ludmilka [50]

Answer: 2.88×10^{24}atoms P_{2}O_{5}

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0.680g P_{2} O_{5} *\frac{1molP_{2} O_{5} }{141.948gP_{2} O_{5} } =4.79mol P_{2} O_{5}

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4.79molP_{2} O_{5} *\frac{6.022X10^{23} }{1mol} =2.88*10^{24}

With this information, we know that there are 2.88X10^{24} total atoms in 0.680 grams P_{2} O_{5}.

I hope this helps! Pls give brainliest!! :)

8 0
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Question 14
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