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matrenka [14]
3 years ago
12

Sea water has about 56.0 grams of NaCl for every 2.0 liters of water. what is the molarity?

Chemistry
1 answer:
Effectus [21]3 years ago
3 0
5.60 cuz I I’m dumb vendbsnksnddn
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4 0
3 years ago
Read 2 more answers
Never been taught this. Need help.
N76 [4]
Definitely not D i would guess A or B
7 0
3 years ago
Please help I really appreciate it thank you ❤️
Feliz [49]

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

#learnwithBrainly

3 0
3 years ago
A student mixes two solutions A and B. A is blue colored and B is yellow colored. The mixture produces has a green color. A ther
Svet_ta [14]

Answer:

A

Explanation:

No temperature change was observed, hence the change is neither exothermic nor endothermic. Hence the answer is A.

4 0
3 years ago
Consider the balanced equation of K I KI reacting with P b ( N O 3 ) 2 Pb(NOX3)X2 to form a precipitate. 2 K I ( a q ) + P b ( N
professor190 [17]

Answer: 50.7 grams

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of KI

\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles

The balanced chemical equation is:

2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)

KI is the limiting reagent as it limits the formation of product and Pb(NO_3)_2 is in excess.

According to stoichiometry :

2 moles of KI give =  1 mole of PbI_2

Thus 0.220 moles of KI give=\frac{1}{2}\times 0.220=0.110moles  of PbI_2

Mass of PbI_2=moles\times {\text {Molar mass}}=0.110moles\times 461.01g/mol=50.7g

Thus 50.7 g of PbI_2 will be formed.

6 0
3 years ago
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