Question

A current of 5.52 a flows along a wire with ℓ = (1.382 i − 2.095 j) m. the wire resides in a uniform magnetic field b = (−0.350 j + 0.550 k) t. what is the magnetic force acting on the wire? (express your answer in vector form.) fb = n

Answer 1

Magnetic force on a wire inside magnetic field is given by formula

$F = i (L X B)here we will haveℓ = (1.382 i − 2.095 j) mB = (−0.350 j + 0.550 k) t.i = 5.52 Anow as per above formula we have[tex]F = 5.52 * (1.382 i − 2.095 j) X (−0.350 j + 0.550 k)$

$F = 5.52* (-0.4837 k - 0.7601 j - 1.152 i)$

$F = - 6.36 i - 4.196 j - 2.670 k$

So magnetic force on the wire is given by above expression with all three components shown with i, j, k.

x component of force is 6.36 N

y component of force is 4.196 N

z component of force is 2.67 N