Answer:
<em>option</em><em> </em><em>C </em><em>5</em>
<em>hope </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> dear</em><em>!</em><em> </em><em>take </em><em>care</em>
Answer:
70g
Explanation:
2*40 of cawill require 112g of cao
50g of ca will require
Ans=70g of cao
Answer:
I would expect to extract the acetic acid.
Explanation:
In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.
In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.
A bimolecular reaction typically takes twice as long as a unimolecular reaction. The answer is true
<h3>
How is activation energy related to temperature?</h3>
- Consider what must occur for ClNO2 to react with NO to understand why reactions have an activation energy.
- First and foremost, these two molecules must clash in order to organise the system.
- Not only must they be brought together, but they must also be kept in precisely the appropriate orientation relative to one other in order for the reaction to occur.
- Some energy must also be used in order to break the Cl-NO2 bond and allow the Cl-NO bond to form.
learn more about bimolecular reaction refer
brainly.com/question/1195122
#SPJ4
Basically stoichiometry is the measurement of elements, that is, the study of chemical quantities consumed or produced in a chemical reaction. When we are performing it we are using a special chemical counting unit: the mole, a unit of measurement, and one mole of a substance contains 6.022 * 10^23 particles. Now mole ratio is defined as the ratio of moles of one substance to the moles of another substance in a balanced equation. <span>If we are looking for the mole ratio between two substances, we need to look at the balanced equations</span> for the coefficients in front of the substances you are interested in.
This should be your guiding mantra for doing stoichiometry problems!