Answer:
son 12.6 gramos de HF 
Explanation:
Tienes que saber qual es el reactor limitante en este caso es fluoruro con los 20 gramos puedes producer .631 mol qual son 12.6 gramos 
 
        
             
        
        
        
Answer:
The answer to your question is 1.1 moles of water
Explanation:
                      2Al(OH)₃  +   3H₂SO₄   ⇒   Al₂(SO₄)₃  +   6H₂O
                        0.45 mol      0.55 mol                                ?
Process
1.- Calculate the limiting reactant
Theoretical proportion
        Al(OH)₃ / H₂SO₄ = 2/3 = 0.667
Experimental proportion
        Al(OH)₃ / H₂SO₄ = 0.45 / 0.55 = 0.81
From the proportions, we conclude that the limiting reactant is H₂SO₄
2.- Calculate the moles of H₂O
                         3 moles of H₂SO₄ ----------------  6 moles of water
                         0.55 moles of H₂SO₄ -----------    x
                         x = (0.55 x 6) / 3
                         x = 3.3 / 3
                         x = 1.1 moles of water
 
        
             
        
        
        
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