Answer:
2.12 L
Explanation:
Data Given:
Amount of O₂ = 5.3 g
Amount of NH₃ = ?
Given Reaction:
4NH₃ + 7O₂ ----------> 4NO₂ +6H₂O
Solution:
for details first we look into the reaction
4NH₃ + 7O₂ ----------> 4NO₂ + 6H₂O
4 mole 7 mol
from reaction we come to know that 4 mole of NH₃ react with 7 mole of O₂
Now we have to convert moles of NH₃ to Liter and mole of O₂ to grams
To convert moles of NH₃ to Liter formula will use
Volume of NH₃ = no. of moles x molar volume at STP
molar volume at STP = 22.4 L/mol
put values in above equation
Volume of NH₃ = 4 mol x 22.4 L/mol
Volume of NH₃ = 89.6 L
Now,
To convert moles of O₂ to grams
mass of O₂ = no. of moles x molar mass
molar mass of O₂ = 2(16) = 32 g/mol
Put values in above equation
mass of O₂ = 7 moles x 32 g/mol
mass of O₂ = 224 g
So,
We come to know that 89.6 L of NH₃ react with 224 g of O₂ to give NO₂ and water then how many liters of NH₃ will react with 5.3 g O₂
Now apply unity formula
89.6 L of NH₃ ≅ 224 g of O₂
X L of NH₃ ≅ 5.3 g of O₂
Do cross multiplication
Liter of NH₃ = 89.6 L x 5.3g / 224 g
Liter of NH₃ = 2.12 L
So
option 2 is correct that is 2.12 Liter of NH₃ will react with 5.3 g O₂
