Ask question

Ask question

All categories

3 years ago

7

A solid and a liquid are shaken together in a test tube to produce a clear blue liquid. Which of the following best describes th

e behavior of the above pair of substances?

1 answer:

harkovskaia [24]3 years ago

6 0

<span>the behavior of the above pair of substances</span> is soluble

You might be interested in

Which of the following best describes a solid?

yuradex [85]

The answer is B) fills all the space in its container

6 0

3 years ago

Read 2 more answers

If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w

irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

C + O₂ -------------> CO₂

1 mol 1 mol 1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

C + O₂ -------------> CO 1 mol (12 g/mol) 1 mol (32 g/mol) 1 mol (44 g/mol)

C + O₂ -------------> CO₂

12 g 32 g 44 g

So,

we come to know that 32 g of Oxygen combine with 12 g of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

32 g of O₂ ≅ 12 g of C

11 g of O₂ ≅ g of C

by doing cross multiplication

g of C = 12 g x 11 g / 32 g

g of C = 132 g / 32 g

g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

12 g of C ≅ 44 g of CO₂

4.13 g of C ≅ g of CO₂

by doing cross multiplication

g of CO₂ = 44 g x 4.13 g / 12 g

g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0

3 years ago

If the vapor pressure of ethanol at 34.7degree C is 100

saw5 [17]

Answer:

we will use the Clausius-Clapeyron equation to estimate the vapour pressures of the boiling ethanol at sea level pressure of 760mmHg:

ln (P2/P1) = $\frac{ΔvapH}{R}([tex]\frac{1}{T1}$ - $\frac{1}{T2}$ )

where

P1 and P2 are the vapour pressures at temperatures T1 and T2

Δ vapH = the enthalpy of vaporization of the ETHANOL

R = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

; T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

T 2 =T⁻²=?

Δ vap H = 38.6 kJ/mol

R = 0.008314 kJ⋅K -1 mol -1

ln ( 760/10)=(0.00325 - T⁻²) (38.6kJ⋅mol-1 /0.008314 )

0.0004368=(0.00325 - T⁻²)

T⁻²=0.002813

T² = 355.47K

6 0

3 years ago

A solution has a Ph of 3.73. The pOH of this solution is?

ollegr [7]

PH + pOH = 14.
So, subtract 3.73 from 14.

The pOH is 10.27 :)

7 0

3 years ago

Uranium is an element that is often used in nuclear power plants. Uranium atoms are very large, and the substance can be dangero

Allushta [10]

same number of protons and different number of neutrons are called isotopes

6 0

3 years ago