All categories

3 years ago

Select the statement that best justifies the conclusion based on the given information.

Mathematics

2 answers:

adoni [48]3 years ago

8 0

Your Answer Is C. Distributive

dedylja [7]3 years ago

6 0

Answer:

C. Distributive

Step-by-step explanation:

You might be interested in

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

3 years ago

A dilation with a scale factor of 15 and centered at the origin is applied to MN¯¯¯¯¯¯¯ with endpoints M(−2, −4) and N(1, 5) .

Nutka1998 [239]

<span>coordinates m' is going to be (-2/5,-4/5)

</span><span>coordinates n' is going to be (1/5,1)

</span>I just took the test i hope this helps!

5 0

3 years ago

Read 2 more answers

The cost for a pack of 8 padlocks is 19.20. Find the unit price in dollars per padlock. if necessary, round your answer to the n

muminat

19.2 / 8 = 2.4
$2.40 is your answer

5 0

4 years ago

Help me please......

Artemon [7]

Answer:

pints: 2 4 7 10 12

quarts: 0 2 4 5 12

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Let f(x) be a func. satisfying f(-x)=f(x) for all real x.if f"(x) exist, find its value.

OverLord2011 [107]

Answer:

$f''(x)=f''(-x)$

Step-by-step explanation:

A function satisfying the equation $f(x)=f(-x)$ is said to be an even function. This denomination comes from the fact that the same relation is satisfied for functions of the form $x^{n}$ with $n$ even. Observe that if $f$ is twice differentiable we can derivate using the chaing rule as follows:

$f(x)=f(-x)$ implies $f'(x)=f'(-x)\cdot (-1)=-f'(-x)$

Applying the chain rule again we have:

$f'(x)=-f'(-x)$ implies $f''(x)=-f''(-x)\cdot (-1)=f''(-x)$

So we have that function $f''(x)$ is also an even function.

4 0

4 years ago