3 years ago

What is the distance between points F and G? (Picture below)

Mathematics

2 answers:

attashe74 [19]3 years ago

8 0

-6+x=12 it’s obviously 18 units apart

Sonbull [250]3 years ago

6 0

Answer:

Step-by-step explanation:

The distance is 12 - (-6) = 12 + 6 = 18

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If 5x+10y=−3 is a true equation, what would be the value of 5x+10y+7?

solong [7]

Answer:

Step-by-step explanation:

5x + 10y = − 3.... (given)

Adding 7 on both sides,

5x + 10y + 7 = - 3 + 7

5x + 10y + 7 = 4

3 0

3 years ago

QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Find the exact values of the six trigonometric functions for angle theta in standard positi

DIA [1.3K]

x = -6, y = 6, Now find the hypotenuse:

(-6)² + (6)² = hypotenuse²

36 + 36 = hypotenuse²

2(36) = hypotenuse²

√2(36) = hypotenuse

6√2 = hypotenuse

$sin\ \theta=\dfrac{y}{hypotenuse}=\dfrac{6}{6\sqrt2}=\dfrac{1}{\sqrt2}\cdot \dfrac{\sqrt2}{\sqrt2}=\boxed{\dfrac{\sqrt2}{2}}\\\\\\cos\ \theta=\dfrac{y}{hypotenuse}=\dfrac{-6}{6\sqrt2}=-\dfrac{1}{\sqrt2}\cdot \dfrac{\sqrt2}{\sqrt2}=\boxed{-\dfrac{\sqrt2}{2}}\\\\\\tan\ \theta=\dfrac{y}{x}=\dfrac{-6}{6}=\boxed{-1}\\\\\\csc\ \theta=\dfrac{hypotenuse}{y}=\dfrac{6\sqrt2}{6}=\boxed{\sqrt2}\\\\\\sec\ \theta=\dfrac{hypotenuse}{x}=\dfrac{6\sqrt2}{-6}=\boxed{-\sqrt2}$