provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its worki
ng fluid. The turbine and pump operate adiabatically. The rate of energy input to the collectors from solar radiation is 0.3 kW per m2 of collector surface area, with 60% of the solar input to the collectors absorbed by the refrigerant as it passes through the collectors. Determine the solar collector surface area, in m2 per kW of power developed by the plant. Discuss possible operational improvements that could reduce the required collector surface area
1 answer:
Answer:
hello some parts of your question is missing attached below is the missing part ( the required fig and table )
answer : The solar collector surface area = 7133 m^2
Explanation:
Given data :
Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2
percentage of solar power absorbed by refrigerant = 60%
Determine the solar collector surface area
The solar collector surface area = 7133 m^2
attached below is a detailed solution of the problem
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Question:
The question is incomplete. The table of value was not added to your question. Below is the table of value and the plotted graph attached.
p R= VCM/AC p/R
0.0001 1 0.0001
0.0005 1.7 0.000294
0.001 3 0.000333
0.005 6 0.000833
0.01 8 0.00125
0.05 10 0.005
Answer:
(a) Yes
(b) W.C = 9.1428
(c) mass of activated carbon = 27.35 Ib-mole/activated carbon
Explanation:
(a) From the graph attached, it is evident that Langmuir isotherm fits the data well. So, the answer is yes.
(b)
Since the input stream has a VCM partial pressure of 0.02 psia, this would be used to find working capacity of activated carbon.
From the graph it can be found by interpolation that p/R value corresponding to 0.02 psia is 0.0021876. Thus R = 9.1428 = WC
It should be noted that in adsorption process, activated carbon is in equilibrium with 0.001 psia of VCM. Thus, from the data R= 1 i.e. this amount of VCM is not adsorbed and lost. This value may be deducted based on the definition of working capacity (WC).
(c)
The molar flow rate of VCM = 1000*62.3*0.02/379*60*14.7
= 0.003739 Ib-mole/hr
Mass of activated carbon required = 0.003739 *8*9.1428*100
= 27.35 Ib-mole/AC
Answer:
11.65 minutes.
Explanation:
See the attached picture for detailed explanation.
