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tino4ka555 [31]
1 year ago
7

At the beginning of last year, tarind corporation budgeted $1,000,000 of fixed manufacturing overhead and chose a denominator le

vel of activity of 500,000 machine-hours. At the end of the year, tari's fixed manufacturing overhead budget variance was $14,000 favorable. Its fixed manufacturing overhead volume variance was $20,000 favorable. Actual direct labor-hours for the year were 525,000. What was tari's total standard machine-hours allowed for last year's output?.
Engineering
1 answer:
maxonik [38]1 year ago
7 0

The tari's total standard machine-hours allowed for last year's output 600,000 hours

Budgeted at start of year:  $100,000 fixed manufacturing overhead  for 500,000 machine hours

Standard = $100,000 / 500,000 hours = $0.2 fixed overhead / maching hour

At end of year, manufacturing overhead volume was $20,000 favorable which means

$20000 / $1=0.2 = 100000 additional hours.

Total Standard Machine Allowance Allowed for output = 500,000 + 100,000 = 600,000 hours.

the use of one machine running for an hour as a basis for cost estimation and operating effectiveness evaluation. In order to determine the contribution margin per machine hour for a specific product: a. Total cost per unit divided by the quantity of machine hours required to produce each unit of the target product. The manufacturing overhead cost divided by the activity driver yields the predetermined overhead rate. For instance, if machine hours were the activity driver, you would divide overhead costs by the anticipated number of machine hours.

Learn more about machine hours here:

brainly.com/question/14298561

#SPJ4

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4 0
3 years ago
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Answer:

Explanation:

The density of the unit cell of a material, Iron in this case, has to be approximately equal  with its experimental value of 7.87 g/cm³.

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For a BCC crystal structure the length of the side of the cube is given by:

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first we will convert this radius to cm since we want the density in g/cm³:

0.124 nm x  1 x 10⁻⁷ cm / nm = 1.24 x 10⁻⁸ cm

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the volume of the cubic cell is:

v = a³ =  ( 2.86 x 10⁻⁸ cm )³ =2.35 x 10⁻²³ cm³

The mass of iron in the body centered cubic cell is obtained from the mass of the atoms in it:

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m = 2 atoms/unit cell x 1 mol/ 6.022 x 10²³ atoms  x 55.85 g/mol

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Therefore,

d = m/v = 1.85 x 10⁻²² g / 2.35 x 10⁻²³cm³ = 7.88 g/cm³

An excelent agreement which confirms that the density of the BCC unit cell agrees with the experimental value.

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4 years ago
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3 years ago
A supply fan is operating at 30000 cfm and 4 inch of water with an efficiency of 50%. (a) Calculate the fan power at the current
serg [7]

Answer:

The pressure and power of fan is 1.77 and 11.18 Hp respectively.

Explanation:

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(A)

From the formula of fan power,

     P _{1}  = \frac{Q \Delta P}{6356 \eta}

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(B)

Fan power and pressure is given by,

We know that pressure difference is proportional to the square of discharge.

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Fan power proportional to the cube of discharge.

       \frac{P_{2} }{P^{1} }  = (\frac{Q_{2} }{Q_{1} } )^{3}

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Therefore, the pressure and power of fan is 1.77 and 11.18 Hp respectively.

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Answer:

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