A large retirement village has a total retail employment of 120. All 1600 of the households in this village consist of two nonwo
rking family members with household income of $20,000. Assuming that shopping and social/recreational trip rates both peak during the same hour (for exposition purposes), predict the total number of peak-hour trips generated by this village using the trip generation models of:_________.
Number of peak hour vehicle based shopping trips per household 0.12
+0.09(household size)
+0.011 (annual house income in thousands of dollors)
-0.15(retail employees in household s neighborhood, in hunreds)
Number of peak hour vehicle based social/recreactional trips per household
= 0.04 + 0.018 (household size)
+0.009(annual house income in thousands of dollors)
+0.16( number of nonworking household members)
Number of peak hour vehicle based shopping trips per household 0.12
+0.09(household size)
+0.011 (annual house income in thousands of dollors)
-0.15(retail employees in household s neighborhood, in hunreds)
Number of peak hour vehicle based social/recreactional trips per household
= 0.04 + 0.018 (household size)
+0.009(annual house income in thousands of dollors)
+0.16( number of nonworking household members)
1 answer:
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Answer:
The power is
Explanation:
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Answer:
The answers are as follow:
a) 10 mm
b) 12.730 N/
c) 127.307 N/
d) 0.25
Explanation:
d1 = 10mm , L1 = 40 mm, L2 = 50 mm, reduction in area = 90% = 0.9
Force = F =1000 N
let us find initial area first, A1 = pi* = 78.55
using reduction in area formula : 0.9 = (A1 - A2 ) / A1
solving it will give, A2 = 0.1 A1 = 7.855
a) The specimen elongation is final length - initial length
50 - 40 = 10 mm
b) Engineering stress uses the original area for all stress calculations,
Engineering stress = force / original area = F / A1 = 1000 / 78.55
Engineering stress = 12.730
c) True stress uses instantaneous area during stress calculations,
True fracture stress = force / final area = F / A2 = 1000 / 7.855
True Fracture stress = 127.30
e) strain = change in length / original length
strain = 10 / 40 = 0.25