A large retirement village has a total retail employment of 120. All 1600 of the households in this village consist of two nonwo
rking family members with household income of $20,000. Assuming that shopping and social/recreational trip rates both peak during the same hour (for exposition purposes), predict the total number of peak-hour trips generated by this village using the trip generation models of:_________.
Number of peak hour vehicle based shopping trips per household 0.12
+0.09(household size)
+0.011 (annual house income in thousands of dollors)
-0.15(retail employees in household s neighborhood, in hunreds)
Number of peak hour vehicle based social/recreactional trips per household
= 0.04 + 0.018 (household size)
+0.009(annual house income in thousands of dollors)
+0.16( number of nonworking household members)
Number of peak hour vehicle based shopping trips per household 0.12
+0.09(household size)
+0.011 (annual house income in thousands of dollors)
-0.15(retail employees in household s neighborhood, in hunreds)
Number of peak hour vehicle based social/recreactional trips per household
= 0.04 + 0.018 (household size)
+0.009(annual house income in thousands of dollors)
+0.16( number of nonworking household members)
1 answer:
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Answer:
The value of Modulus of elasticity E = 85.33 ×
Beam deflection is = 0.15 in
Explanation:
Given data
width = 5 in
Length = 60 in
Mass of the person = 125 lb
Load = 125 × 32 = 4000
We know that moment of inertia is given as
I = 1.40625
Deflection = 0.15 in
We know that deflection of the beam in this case is given as
Δ =
E = 85.33 ×
This is the value of Modulus of elasticity.
Beam deflection is = 0.15 in
Answer:
the graph and the answer can be found in the explanation section
Explanation:
Given:
Network rated voltage = 24 kV
Impedance of network = 0.07 + j0.5 Ω/mi, 8 mi
Rn = 0.07 * 8 = 0.56 Ω
Xn = 0.5 * 8 = 4 Ω
If the alternator terminal voltage is equal to network rated voltage will have
Vt = 24 kV/√3 = 13.85 kV/phase
The alternative current is
The impedance Zn is
The voltage drop is
rac = 1.2rdc = 1.2 * 7.476 = 8.97 Ω
The effective armature resistance is
The induced voltage for leading power factor is
if cosθ = 0.5
if cosθ= 0.6
EF = 12790.8 V
if cosθ = 0.7
EF = 13731.05 V
if cosθ = 0.8
EF = 14741.6 V
if cosθ = 0.9
EF = 15809.02 V
if cosθ = 1
EF = 13975.6 V
The voltage regulation is
For each value:
if cosθ = 0.5
voltage regulation = -13.8%
if cosθ = 0.6
voltage regulation = -7.6%
if cosθ = 0.7
voltage regulation = -0.85%
if cosθ = 0.8
voltage regulation = 6.4%
if cosθ = 0.9
voltage regulation = 14%
if cosθ = 1
voltage regulation = 0.9%
the graph is shown in the attached image
for 10% of regulation the power factor is 0.81
