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Olin [163]
3 years ago
6

Combined Gas Law

Chemistry
1 answer:
creativ13 [48]3 years ago
6 0
Idkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
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Ammonium hydrogen sulfide (NH4HS) can
Sergeu [11.5K]

K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}} is the equilibrium constant expression for

NH₂HS(S)   →   NH₂(g) + H₂S(g). Hence, option A is correct.

<h3>Definition of equilibrium constant.</h3>

A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

Equilibrium constant for the NH₂HS(S)   →   NH₂(g) + H₂S(g) will be:

K_c = \frac{[Product]^{coefficient}}{[Reactantt]^{coefficient}}

K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}}

Hence, option A is correct.

Learn more about the equilibrium constant here:

brainly.com/question/10038290

#SPJ1

8 0
3 years ago
1. When you are underwater, sounds that you hear from above the water sound much quieter than when you are not underwater. Draw
GuDViN [60]

Answer:

Explanation:

the water make it sound different then above water

hop this helps

5 0
3 years ago
1.) Calculation: If 9.02 x 1024 particles of vinegar (HC2H3O2)HC2H3O2) are added to 16.5 moles of eggshell (CaCO3) and 6.35 mole
blsea [12.9K]

The theoretical yield of acetate is 2607 g. The actual yield of acetate is 1066.8 g. The percentage yield of acetate is 41%.

If 1 mole of vinegar contains 6.02  x 10^23 particles

x moles of vinegar contains 9.02 x 10^24 particles

x = 1 mole x 9.02 x 10^24 /6.02 x 10^23

x = 15 moles of vinegar

The reaction is as follows;

2HC2H3O2 + CaCO3 -----> Ca(C2H3O2)2 + H2O + CO2

Since 2 moles of vinegar reacts with 1 mole of carbonate

x moles of vinegar reacts with 16.5 moles of carbonate

x =  2 moles x 16.5 moles/ 1 mole

x = 33 moles of vinegar

We can see that the vinegar is the reactant in excess hence the carbonate is the limiting reactant.

Theoretical yield = 16.5 moles x 158 g/mol = 2607 g

Actual yield = 6.35 moles  x 158 g/mol = 1066.8 g

Percent yield = 1066.8 g/2607 g × 100/1

= 41%

Learn more: brainly.com/question/13440572?

7 0
3 years ago
Suppose that you use a pair of chopsticks and apply a force of 1 N over a distance of 0.01 m. How much work do you do? If the ou
Leto [7]

Explanation:

Work done = force * perpendicular distance

= 1 * 0.01 = 0.01 joules

7 0
3 years ago
Calculate the molarity of 0.50 mol MgCl2 in 750 ml of solution.
Vedmedyk [2.9K]

Answer : The correct answer for molarity of MgCl₂ solution is 0.67 M.

Molarity :

It expresses concentration of any solution . It can be defined as mole of solute present in volume of solution in Liter .

It uses unit M or \frac{mol}{L}

It can be formulated as :

Molarity (\frac{mol}{L} ) = \frac{mole of solute (mol)}{volume of solution (L)}

Given : mol of MgCl₂ (solute ) = 0.50 mol

Volume of solution = 750 mL

Following steps can be done :

Step 1 ) To convert volume of solution from mL to L

1 L = 1000 mL

Volume of solution = 750 mL * \frac{1 L}{1000mL}

Volume of solution = 0.750 L

Step 2) To find molarity

Plugging mole of solute and volume of solution in molarity formula as :

Molarity = \frac{0.50 mol}{0.750 L }

Molarity = 0.67 \frac{mol}{L}

Hence molarity of MgCl₂ solution is 0.67 M

4 0
4 years ago
Read 2 more answers
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