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Umnica [9.8K]
3 years ago
14

Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A

and container B are glass spheres connnected by a tube with a stopcock. Container A is larger than container B. If the gases are allowed to mix together, what is the resulting pressure
Chemistry
1 answer:
horsena [70]3 years ago
4 0

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}

P_f = \dfrac{2.80*717+4.30*174}{717+174}

P_f = \dfrac{2007.6+748.2}{891}

P_f = \dfrac{2755.8}{891}

\mathbf{P_f =3.09 \ atm}

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