Question

What similarity property, if any, can be used to show that the following two triangles are similar ?

Answer 1

Answer:

A) SSS

Step-by-step explanation:

We have,

$\frac{AC}{DF}=\frac{10}{15}=\frac{2}{3}\\\frac{AB}{DE}=\frac{12}{18}=\frac{2}{3}\\\frac{BC}{EF}=\frac{8}{12}=\frac{2}{3}\\\text{Thus,}\\\frac{AC}{DF}=\frac{AB}{DE}=\frac{BC}{EF}$

Since the sides are in proportion, the two triangles are similar by the SSS test.