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Degger [83]
3 years ago
9

3. You are flying 2586 miles from San Francisco to New York. An hour into the flight, you are 600

Physics
2 answers:
Andrei [34K]3 years ago
6 0

Answer:

268.22 m/s

Explanation:

An hour into the flight, you are 600 miles from San Francisco.

This sentence says that speed is 600 mi/h.

Now we need to convert it into m/s.

1 mi = 1609.34 m

1 h = 60 min = 60 min *60 s/1min = 3600 s

600 mi/h * 1609.34 m/1 mi * 1h/ 3600s= 600*1609.34/3600 m/s= =268.22 m/s

Citrus2011 [14]3 years ago
3 0

Answer:

268.2 m/s (1dp)

Explanation:

600 miles = 965,606m (1mile = 1609.34m)

965606/60 = 16,0943.43 ..... (metres traveled every minute)

16,0943.43/60 = 268.2238 .....

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Two particles, each with charge Q, and a third charge q, are placed at the vertices of an equilateral triangle as shown. The tot
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Answer:

<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>

Explanation:

The image is shown below.

The force on the particle with charge q due to each charge Q = \frac{kQq}{r^{2} }

we designate this force as N

Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.

Resolving the forces on the particle, we have

for the x-component

N_{x} = N cosine 60° + (-N cosine 60°) = 0

for the y-component

N_{y} = -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N

The above indicates that there is no resultant force in the x-axis, since it is equal to zero (N_{x} = 0).

The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.

<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>

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3 years ago
a 2,000-kilogram railroad car moving at 8m/s to the right collides with a 6,000-kilogram railroad car moving at 3m/s to the west
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A car is moving in uniform circular motion. If the cars speed were to double to keep the car moving with the same radius the acc
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Answer:

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Explanation:

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The circular motion is described when an object rotates about a fixed point called center. The distance from the object to the center is the radius. There are other magnitudes in the circular motion like the angular speed, tangent speed, and centripetal acceleration. The formulas are:

v_t=w\ r

\displaystyle a_c=\frac{v_t^2}{r}

If the speed is doubled and the radius is the same, then

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