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3 years ago

Discuss the chemical bond exist in silicon crystal?

2 answers:

8 0

Covalent bonds. Silicon, carbon, germanium, and a couple of different components structure covalently reinforced solids. In these components there are four electrons in the external sp-shell, which is half filled. ... In the covalent bond a particle shares one valence (external shell) electron with every one of its four closest neighbor iotas.

tamaranim1 [39]3 years ago

6 0

Covalent bonds. Silicon, carbon, germanium, and a few other elements form covalently bonded solids. In these elements there are four electrons in the outer sp-shell, which is half filled. ... In the covalent bond an atom shares one valence (outer-shell) electron with each of its four nearest neighbour atoms.

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What are things measured by mass

Free_Kalibri [48]

Anything that is possibly solid or can be contained in a solid

Mass is the amount of matter that is contained in a certain object.
Like
20 kg
10 g
100 lb

6 0

3 years ago

A 0.5 kg block slides down a frictionless semicircular track from a height, h, and collides with a second 1.5 kg block at the bo

Ede4ka [16]

Answer:

$h' = 0.062\cdot h$

Explanation:

The speed of the 0.5 kg block just before the collision is found by the Principle of Energy Conservation:

$U_{g} = K$

$m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}$

$v = \sqrt{2\cdot g \cdot h}$

$v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot h}$

$v \approx 4.429\cdot \sqrt{h}$

Knowing that collision is inelastic, the speed just after the collision is determined with the help of the Principle of Momentum Conservation:

$(0.5\,kg) \cdot (4.429\cdot \sqrt{h}) = (2\,kg)\cdot v$

$v = 1.107\cdot \sqrt{h}$

Lastly, the height reached by the two blocks is:

$K = U_{g}$

$\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot h'$

$h' = \frac{v^{2}}{2\cdot g}$

$h' = \frac{(1.107\cdot \sqrt{h})^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$h' = 0.062\cdot h$

3 0

3 years ago

Why is it important for the path of a circuit to be circular?

vredina [299]

Answer:

When the platform rotates, the rotating mass will travel in a circular path due to the force exerted on it by the string (by way of the tension in the spring). Since it is not possible to have an instantaneous readout of this tension force while the platform is rotating, an indirect measurement of this force will be made using the weight of the static mass as shown and explained below.

4 0

3 years ago

Read 2 more answers

Please show work with the answer and thank you

Alika [10]

Answer:

its your homework

Explanation:

you aren't getting any free answers out of me because it sounds like your trying to be smart your welcome

(Not smarter than me)

7 0

3 years ago