While riding in a hot air balloon,
which is steadily at a speed of 1.01 m/s, and your phone accidentally falls.
<span>(a)
</span>The
speed of your phone after 4 s is:
V= u +
at
V= 1.01
+ (9.8)(4)
V=
40.21 m/s
<span>(b)
</span>The balloon
is ____ far:
V = u +
at
V= 1.01
+ (9.8)(1)
V=10.81
–distance at 1 one second
V= u +
at
V= 1.01
+ (9.8)(2)
V= 20.61-distance
at 2 seconds
V= u+ at
V=
30.41- distance at 3 seconds
V=
40.21- distance at 4 seconds
D=
102.04 m
<span>(c)
</span>If the
balloon is rising steadily at 1.01 m/s:
V= -1.1
m/s
<span> </span>
Johannes Kepler- he did it by observing the ‘Tycho Brahe’. His 3rd law was published 10 years later to his first two laws.
Answer:
the maximum height reached by the object from where it was launched is 0.4591 m
Explanation:
initial speed of the object, u= 3 m/s
The velocity at the maximum height will always be 0.
Therefore, final velocity, v= 0 m/s
Using the Newton's equation of motion,
v^2 - u^2 = 2*g*h(max)
0 - u^2= 2*g*h(max)
h(max) = -u^2 /2* g
where g is the gravitational acceleration.
g= - 9.8 m/s^2
substituting the values in equation,
h(max)= - (3*3) / 2*(-9.8)
h(max) = 0.4591 m
the maximum height reached by the object from where it was launched is 0.4591 m
learn more about maximum height reached here:
<u>brainly.com/question/20001249</u>
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