The relationship between a cathode and an anode involves

2 answers:

8 0

Cathode and anode always go together in electrochemical reactions. An example of this is the lead battery. The lead battery contains a chemical that is involved in the chemical reaction. The chemical reaction in the battery causes a buildup of electrons in the anode. And because the electron buildup in the anode is full, its only place to go is the cathode. The movement of the electrons from anode to cathode is caused by the chemical reaction present in the battery. There will be a movement until the chemical runs out. If the chemical runs out, the electrons stop moving. The answer is c.

Hatshy [7]3 years ago

5 0

THE ANSWER IS *ELECTRONS* I toojk the pen foster exam! <3 hope this helps

You might be interested in

Which order shows decreasing momentum?

klio [65]

Answer:

Explanation: Decreasing in velocity

4 0

3 years ago

Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca

OverLord2011 [107]

Answer:

E = -4000 N / C

Explanation:

The potential and electric field are related

V = - E s

E = - V / s

we reduce the magnitudes to the SI system

s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

E = - 16 /0.004

E = -4000 N / C

8 0

3 years ago

Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.

Step2247 [10]

The masses have no inertia about their own CM, and "the object" is the two masses. 
1. Icm (at point A) = 2mr^2
hope this helps

3 0

3 years ago

How do you make a mirages?

Aleksandr [31]

Answer:

when the ground is very hot and the air is cool.

Explanation:

The hot earth warms a layer of air right above the ground. Light is refracted as it passes through the cool air and onto the hot air sheet (bent). A coating of very warm air near the earth bends the light from the sky almost into a U-shaped bend.

7 0

3 years ago

Read 2 more answers

In one cycle a heat engine absorbs 450 J from a high-temperature reservoir and expels 290 J to a low-temperature reservoir. If t

Vitek1552 [10]

Answer:

So the ratio will be $\frac{T_L}{T_H}=-0.171$