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Lerok [7]
3 years ago
9

The relationship between a cathode and an anode involves

Physics
2 answers:
yulyashka [42]3 years ago
8 0
<span>Cathode and anode always go together in electrochemical reactions. An example of this is the lead battery. The lead battery contains a chemical that is involved in the chemical reaction. The chemical reaction in the battery causes a buildup of electrons in the anode. And because the electron buildup in the anode is full, its only place to go is the cathode. The movement of the electrons from anode to cathode is caused by the chemical reaction present in the battery. There will be a movement until the chemical runs out. If the chemical runs out, the electrons stop moving. The answer is c.</span>
Hatshy [7]3 years ago
5 0

THE ANSWER IS<u> *</u><u><em>ELECTRONS* </em></u> I toojk the pen foster exam! <3 hope this helps

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valentina_108 [34]
Change in Momentum =  mv - mu.

u = 0, v = 10 m/s.  Note ball accelerated from rest, so initial velocity = 0. u =0

Change in Momentum =  mv - mu = 3*10 - 3*0 =30.

Change in Momentum = 30 kgm/s.

4 0
3 years ago
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Which type of power plants generate the least amount of pollution? A) Biomass power plants B) Geothermal power plants C) Nuclear
sladkih [1.3K]

Answer:

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Explanation:

6 0
3 years ago
Which value would complete the last cell?
GREYUIT [131]

Answer:

4.0

Explanation:

The following data were obtained from the question:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

Force is simply defined as the product of mass and acceleration. Mathematically, it is expressed as

Force (F) = mass (m) x acceleration (a)

F = ma

With the above formula, we can obtain th acceleration of the body as follow:

Force (F) = 20 N

Mass (m) = 5 kg

Acceleration (a) =.?

F = ma

20 = 5 x a

Divide both side by 5

a = 20/5

a = 4 m/s²

Therefore, the value that will complete the last cell in the question above is 4.

5 0
4 years ago
Two children are riding on the edge of a merry-go-round that has a mass of 100.kg and radius of 1.60m and is rotating at 20.0rpm
Gre4nikov [31]

Here since both children and merry go round is our system and there is no torque acting on this system

So we will use angular momentum conservation in this

I_1\omega_1 = I_2\omega_2

now here we have

I_1 = \frac{MR^2}{2} + m_1R^2 + m_2R^2

I_1 = \frac{100(1.60)^2}{2} + (22 + 28)(1.60)^2

I_1 = 256

Now when children come to the position of half radius

then we will have

I_2 = \frac{MR^2}{2} + m_1(\frac{R}{2})^2 + m_2(\frac{R}{2})^2

I_2 = \frac{100(1.6)^2}{2} + (28 + 22)(0.8)^2

I_2 = 160

now from above equation we have

256 (20.0 rpm) = 160(\omega_2)

\omega_2 = 32 rpm

8 0
3 years ago
A force can effect the ___ of an object
harina [27]
Movement..............
7 0
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