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Lerok [7]
3 years ago
9

The relationship between a cathode and an anode involves

Physics
2 answers:
yulyashka [42]3 years ago
8 0
<span>Cathode and anode always go together in electrochemical reactions. An example of this is the lead battery. The lead battery contains a chemical that is involved in the chemical reaction. The chemical reaction in the battery causes a buildup of electrons in the anode. And because the electron buildup in the anode is full, its only place to go is the cathode. The movement of the electrons from anode to cathode is caused by the chemical reaction present in the battery. There will be a movement until the chemical runs out. If the chemical runs out, the electrons stop moving. The answer is c.</span>
Hatshy [7]3 years ago
5 0

THE ANSWER IS<u> *</u><u><em>ELECTRONS* </em></u> I toojk the pen foster exam! <3 hope this helps

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The diagram below shows the stars that are nearest to our solar system.
abruzzese [7]

Answer:

no u tried of the same dam

thing

Explanation:

7 0
4 years ago
Derive the expression for the equivalent resistance of three resistors in[1] paraleli [2] series
sergeinik [125]
The total resistance of an electric circuit with resistors widener series in the sum of the individual resistances:
Each resistor in a series circuit has a same amount of current flowing through it.
Each resistor in a parallel circuit has the same for voltage of the source applied to it.

When was this is are connected in parallel, the supply current is equal to the sum of the current through each resistor. In other words the currents in the branches of a parallel circuit add up to the supply current. When resistors are connected in parallel they have the same potential differences across them.
8 0
4 years ago
A uniform thin spherical shell of mass M=2kg and radius R=0.23m is given an initial angular speed w=18.3rad/s when it is at the
Rashid [163]

Answer:

47.8rad/s

Explanation:

For energy to be conserved.

The potential energy sustain by the object would be equal to K.E

P.E = m× g× h = 2 × 9.81× 3.5= 68.67J

Now K.E = 1/2 × I × (w1^2 - w0^2)

I = 2/3 × M × R2

= 2/3 × 2 × (0.23)^2= 0.0705

Hence

W1 = final angular velocity

Wo = initial angular velocity

From P.E = K.E we have;

68.67J = 1/2 × 0.0705 × (w1^2 - w0^2)

(w1^2 - w0^2) = 1948.09

W1^2 = 1948.09 + (18.3^2)

W1^2=2282.98

W1 = √2282.98

=47.78rad/s

= 47.8rad/s to 1 decimal place.

7 0
3 years ago
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I think its evaporation
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3 years ago
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3 years ago
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