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Ksenya-84 [330]
3 years ago
7

50 POINTS!!!!

Mathematics
1 answer:
Zina [86]3 years ago
6 0

Answer:

Step-by-step explanation:

answer:

3x - 18 = 2y

5x - 6y = 14

5x - 3*(2y) = 14

5x - 3*(3x - 18) = 14

5x - 9x + 54 = 14

-4x = -40

x = 10

3*10 - 18 = 2y

30 - 18 = 2y

12 = 2y

y = 6

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Find the compound amount for the deposit. (Round to two decimal places).
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Problem

If you deposit $5000 into an account paying 7% annual interest compounded yearly , how much money will be in the account after 6 years?

Result

The amount is $7503.65 and the interest is $2503.65. there for i believe the answer is D.

7 0
4 years ago
Read 2 more answers
What is the sign of the product (3)(−25)(7)(−24)?
german

Answer:

- * - = +

then:

(3)(−25)(7)(−24)

= (3*-25)(7*-24)

= (-75)(-168)

= + 12600

The sign is:

+

6 0
4 years ago
BRAINLIEST FOR AN ACTUAL ANSWER
Andreyy89

Answer:

The correct pair of functions is the third one:  h(x)=(x−24)^2 and g(x)=x2

Step-by-step explanation:

Example:  If we have q(x) = x^2 and its graph, moving the vertex of this graph 24 units to the right results in r(x) = (x - 24)^2.

The correct pair of functions is the third one:  h(x)=(x−24)^2 and g(x)=x2

Note:  the fourth pair is incorrect, because the " + " sign moves the graph of x^2 24 units to the left.

3 0
3 years ago
A steady wind blows a kite due west. The kite's height above ground from horizontal position x = 0 to x = 80 ft is given by y =
GaryK [48]

Answer:

The distance travelled by the kite is 122.8 ft ( approx )

Step-by-step explanation:

Here, the given function,

y=150-\frac{1}{40}(x-50)^2

Differentiating with respect to x,

y'=-\frac{1}{20}(x-50)

∵ arc length of a curve is,

L=\int_{a}^{b} \sqrt{1+y'^2}dx

Where, y shows the height of the curve for a ≤ x ≤ b,

Thus, the arc length of the given curve is,

L=\int_{0}^{80} \sqrt{1+(-\frac{1}{20}(x-50)^2}dx

Put -\frac{1}{20}(x-50)=tan\theta

\implies -dx=-20 sec^2\theta d\theta

\implies L=-20\int_{0}^{80} \sqrt{1+tan^2\theta}sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

=-20\int_{0}^{80} (sec \theta ) sec^2\theta d\theta

By integration by parts,

=|-\frac{20}{2}(sec \theta tan\theta +ln|sec\theta +tan\theta |) |^{x=80}_{x=0}

If x = 80, tan \theta = -\frac{1}{20}(30-50)=\frac{3}{2}

sec \theta = \frac{\sqrt{13}}{2}

\implies \theta = \frac{1}{20}(0-50)=\frac{5}{2}

sec \theta = \frac{\sqrt{29}}{2}

Thus, the length of the curve is,

=-10(\frac{\sqrt{13}}{2}(-\frac{3}{2}) +ln|\frac{13}{2}-\frac{3}{2}|) + 10(\frac{5\sqrt{29}}{4} + ln |\frac{29}{2} + \frac{5}{2} |)

\approx 122.8\text{ feet}

8 0
3 years ago
Three questions! Need help.
Dmitrij [34]
Answers:
1. Choice A) Reflection symmetry only
2. Choice B) Rotation symmetry only
3. Choice D) Both types of symmetry

-----------------------------------------------------------------------

Explanations:

The letter K can be reflected over a horizontal line through its center. The upper half will fold over to line up with the lower half. So this shows we have reflection symmetry. We cannot rotate K some angle less than 360 degrees to have the letter line up with itself. So it doesn't have rotation symmetry.

The letter S can be rotated 180 degrees to have it line up with itself. Though it can't be reflected over any line to have it line up one half with the other. So that's why we have rotational symmetry only.

The letter H has both reflection and rotation symmetry. We can reflect H two ways. One line is vertical through the center. The other line is horizontal through the center. We can also rotate H 180 degrees to have it line up with its original image.
8 0
3 years ago
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