Given:
f(x) = 70n - 400 : equation for monthly profit.
n = number of students enrolled in the guitar class.
70 refers to the amount charged per student.
400 is the fixed expense made by the instructor.
For the instructor to have a profit, the product of 70n must be more than 400.
400/70 = 5.7 or 6
There must be at least 6 students enrolled in class for the instructor to generate profit.
f(x) = 70(6) - 400 = 420 - 400 = 20
1000 = 70n - 400
1000 + 400 = 70n
1400 = 70n
1400/70 = n
20 = n
There must be 20 students enrolled in class for the instructor to earn 1000 in profit.
1000 = 70(20) - 400
1000 = 1400 - 400
1000 = 1000
The rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t
So, given that both store A and store B follow the same equations but t is different for them, you can right:
Store A: pA (t) 10,000 (1.075)^t
Store B: pB(t'): 10,000 (1.075)^t'
=> pA(t) / pB(t') = 1.075^t / 1.075^t'
=> pA(t) / pB(t') = 1.075 ^ (t - t')
And t - t' = 0.5 years
=> pA(t) / pB(t') = 1.075 ^ (0.5) = 1.0368
or pB(t') / pA(t) = 1.075^(-0.5) = 0.964
=> pB(t') ≈ 0.96 * pA(t)
Which means that the profit of the store B is about 96% the profit of store A at any time after both stores have opened.
Answer:
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Your answer should be:
Maura runs faster.
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I hope this helped!
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Answer:
The answer is a love
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I've already took this quiz and my answer was a
It would be 15400*0.015=How much he will make
