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Marizza181 [45]
3 years ago
11

chlorine has two naturally occurring isotopes, Cl-35 and Cl-37. The atomic mass of chlorine is 35.45. Which of these two isotope

s of chlorine is more abundant?
Chemistry
1 answer:
Sliva [168]3 years ago
5 0
Cl-35, as the atomic mass of Chlorine (35.45) is closer to the number 35 than to the number 37. A higher abundance of CL-35 isotope would have caused the atomic number (which is an average of the values of all isotopes of a substances taking relative abundance into consideration) to decrease from 36, which would appear to be the average.
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3 years ago
Predict how many grams of KCI is produced from 40 grams of K?
Nutka1998 [239]

Explanation:

firstly find for the molar mass of kcl and molar mass of k

and then

molar mass of k = x

molar mass of kcl= 40

cross mutiply and then simplify you will get your answer

5 0
3 years ago
How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.6 atm) according to 11) the following reaction? Assume t
ddd [48]

Answer:

#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.

Explanation:

Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆

1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.

=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP

2. Calculate moles of F₂ used

=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used

3. Calculate moles of XeF₆ produced from reaction ratios …

Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆

4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number  (6.02 x 10²³ molecules/mole)

=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)

                                  = 2.75 x 10²³ molecules XeF₆.

8 0
3 years ago
How many moles of N2 in 57.1 g of N2?
SpyIntel [72]

We are given –

  • Mass of \bf N_2 is 57.1 g and we are asked to find number of moles present in 57.1 g of \bf N_2

\qquad\pink{\bf\longrightarrow  { Molar \:mass \:of \: N_2:-}  }

\qquad\bf  \twoheadrightarrow 14\times 2

\qquad\bf \twoheadrightarrow   28

\qquad____________________

Now,Let's calculate the number of moles present in 57.1 g of \bf N_2

\qquad\purple{\bf\longrightarrow  { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}

\qquad\bf   \twoheadrightarrow \dfrac{57.1}{28}

\qquad\bf  \twoheadrightarrow 2.04\: moles

__________________________________

7 0
2 years ago
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