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Neko [114]
3 years ago
10

Which of these solutes raises the boiling point of water the most?

Chemistry
2 answers:
Vlad [161]3 years ago
7 0
I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
never [62]3 years ago
7 0

Answer: ionic sodium phosphate (Na_3PO_4)

Explanation:

The formula used:

\Delta T_b=i\times k_b\times m

\Delta T_b= change in boiling point

i = Van'T Hoff factor  

k_b = boiling point constant

m = molality

1.  For LiCl

LiCl\rightarrow Li^{+}+Cl^{-}  

i= 2 as it is ionic and dissociate to give 2 ions.

2. For NaCl

NaCl\rightarrow Na^{+}+Cl^{-}  

i= 2 as it is ionic and dissociate to give 2 ions.

3. For C_{12}H_{22}O_{11}

, i= 1 as it is a non electrolyte and does not dissociate.

4. For Na_3PO_{4}

Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}  

, i= 4 as it is ionic and dissociate to give 4 ions.

5.  For MgBr_{2}

MgBr_2\rightarrow Mg^{2+}+2Br^-  

, i= 3 as it is ionic and dissociate to give 3 ions.

Thus as vant hoff factor is highest for Na_3PO_{4} , the boiling point will be raised most.

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What is the net ionic equation of the reaction of MgSO4 with Pb(NO3)2? Express you answer as a chemical equation including phase
Nady [450]

Answer : The net ionic equation will be,

Pb^{2+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The same number of ions present on reactant and product side which do not participate in a reactions.

The given balanced ionic equation will be,

MgSO_4(aq)+Pb(NO_3)_2(aq)\rightarrow Mg(NO_3)_2(aq)+PbSO_4(s)

The ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+SO_4^{2-}(aq)+Pb^{2+}(aq)+2NO^{3-}(aq)\rightarrow PbSO_4(s)+Mg^{2+}(aq)+2NO^{3-}(aq)

In this equation, Mg^{2+}\text{ and }NO_3^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Pb^{2+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)

4 0
3 years ago
What is the minimum mass of magnetite (Fe,O2), a iron ore, from which 120. g of pure iron could be extracted? Be sure your answe
Schach [20]

Answer:

166 g

Explanation:

Step 1: Write the reaction for the obtaining of Fe from magnetite

Fe₃O₄ ⇒ 3 Fe + 2 O₂

Step 2: Calculate the moles corresponding to 120 g of Fe

The molar mass of Fe is 55.85 g/mol.

120 g × (1 mol/55.85 g) = 2.15 mol

Step 3: Calculate the moles of Fe₃O₄ required to produce 2.15 moles of Fe

The molar ratio of Fe₃O₄ to Fe is 1:3. The moles of Fe₃O₄ required are 1/3 × 2.15 mol = 0.717 mol

Step 4: Calculate the mass corresponding to 0.717 moles of Fe₃O₄

The molar mass of Fe₃O₄ is 231.53 g/mol.

0.717 mol × 231.53 g/mol = 166 g

6 0
3 years ago
How is the atomic mass of an atom calculated?
azamat
Adding the number of protons by the number of neutrons
8 0
3 years ago
Which of the follow describes what happpens to the kinetic energy of water when it changes from the solid state to a liquid stat
Anestetic [448]

Answer:

Kinetic energy increases.

Explanation:

In a solid, molecules do not have much room to move. They are very slow moving, which means that kinetic energy is low. In a liquid, molecules have more room to move. They are able to move faster than a solid, which means that kinetic energy is low.

From greatest to lowest kinetic energy:

gas, liquid, solid

7 0
3 years ago
Does the physical form of the material matter for mass-mole<br> and mole-mass calculations?
natulia [17]
Tin metal reacts with hydrogen fluoride to produce tin(II) fluoride and hydrogen gas according to the following balanced equation.

Sn(s)+2HF(g)→SnF2(s)+H2(g)
Sn(s)+2HF(g)→
SnF
2
(s)+
H
2
(g)

How many moles of hydrogen fluoride are required to react completely with 75.0 g of tin?

Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
1 mol Sn = 2 mol HF (mole ratio)
Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

g Sn → mol Sn → mol HF

Step 2: Solve.

75.0 g Sn×1 mol Sn118.69 g Sn×2 mol HF1 mol Sn=1.26 mol HF
75.0 g Sn×
1
mol Sn
118.69
g Sn
×
2
mol HF
1
mol Sn
=1.26 mol HF

Step 3: Think about your result.

The mass of tin is less than one mole, but the 1:2 ratio means that more than one mole of HF is required for the reaction. The answer has three significant figures because the given mass has three significant figures.
4 0
3 years ago
Read 2 more answers
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