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Neko [114]
3 years ago
10

Which of these solutes raises the boiling point of water the most?

Chemistry
2 answers:
Vlad [161]3 years ago
7 0
I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
never [62]3 years ago
7 0

Answer: ionic sodium phosphate (Na_3PO_4)

Explanation:

The formula used:

\Delta T_b=i\times k_b\times m

\Delta T_b= change in boiling point

i = Van'T Hoff factor  

k_b = boiling point constant

m = molality

1.  For LiCl

LiCl\rightarrow Li^{+}+Cl^{-}  

i= 2 as it is ionic and dissociate to give 2 ions.

2. For NaCl

NaCl\rightarrow Na^{+}+Cl^{-}  

i= 2 as it is ionic and dissociate to give 2 ions.

3. For C_{12}H_{22}O_{11}

, i= 1 as it is a non electrolyte and does not dissociate.

4. For Na_3PO_{4}

Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}  

, i= 4 as it is ionic and dissociate to give 4 ions.

5.  For MgBr_{2}

MgBr_2\rightarrow Mg^{2+}+2Br^-  

, i= 3 as it is ionic and dissociate to give 3 ions.

Thus as vant hoff factor is highest for Na_3PO_{4} , the boiling point will be raised most.

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SiCl4 + H2O = H4SiO4 + HCl
vichka [17]

Hey there!

Balance the equation:

SiCl₄ + H₂O → H₄SiO₄ + HCl

Balance H.

2 on the left, 5 on the right. Add a coefficient of 3 in front of H₂O and a coefficient of 2 in front of HCl.

SiCl₄ + 3H₂O → H₄SiO₄ + 2HCl  

Balance O.

3 on the left, 4 on the right. Change the coefficient of 3 in front of H₂O to a 4.

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This unbalanced our H, so change the coefficient of 2 in front of HCl to a 4.

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Balance Si.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

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