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aniked [119]
3 years ago
15

What is the chemical formula for copper(II) sulfate? CuSOmc026-1.jpg Cumc026-2.jpgSOmc026-3.jpg CuS Cumc026-4.jpgS

Chemistry
2 answers:
Sati [7]3 years ago
8 0
The chemical Formula is CuSO4
jeyben [28]3 years ago
5 0

Answer: CuSO_4

Explanation: For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here Copper is having an oxidation state of +2 and sulfate is a polyatomic ion with oxidation state of -2. Thus they combine to form neutral CuSO_4.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

Cu^{2+}+SO_4^{2-}\rightarrow CuSO_4

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How can one kg of iron melt more ice than 1 kg lead at 100 °C
Vanyuwa [196]

Answer:

Due to the specific heat capacity of iron, 0.444 J/(g·°C), is more than the specific heat capacity for lead, 0.160 J/(g·°C)

Explanation:

The given parameters are;

The metals provided to melt the ice and their temperature includes;

One kg (1000 g) of iron;

Specific heat capacity = 0.444 J/(g·°C)

Temperature = 100°C

1 kg (1000 g) of lead

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Temperature = 100°C

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ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{iron} = Heat obtained from the iron by the ice

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Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

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Mass of ice melted by the iron = 44400 J/334 (J/g) ≈ 132.9 g

Mass of ice melted by the iron ≈ 132.9 g

For lead, we have;

ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{lead} = Heat obtained from the iron by the ice

ΔQ_{lead} = 0.160 m × 1000 × (100 - 0) = 16000 J

Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

∴ Heat absorbed by the ice for melting, H_l = Mass of ice × Latent heat of ice

H_l = Mass of ice × 334 J/g = 16000 J

Mass of ice melted by the lead = 16000 J/334 (J/g) ≈ 47.9 g

Mass of ice melted by the lead ≈ 47.9 g

Therefore, mass of  ice melted by the iron, approximately 132.9 g, is more than mass of ice melted by the lead, approximately 47.9 g.

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